Answer:
P(A) = 5/12
P(B) = 1/2
Step-by-step explanation:
A) Sum greater than 7
If the sum needs to be >7, then it can be 8, 9, 10, 11, and 12.
There are 26 out of 36 events where the sum is >7, thus P(A) = 15/36 = 5/12.
B) Sum is even
If we see in an overview of the sum distribution, there is a balanced division between odd and even numbers, thus the probability is very likely to be 1/2. Now let's make sure of it:
If the sum needs to be even, which means divisible by 2, then it can be 2, 4, 6, 8, 10, and 12.
There are 18 out of 36 events where the sum is even, thus P(B) = 18/36 = 1/2.
Image of table for reference: https://qph.fs.quoracdn.net/main-qimg-1283a98bd649f522986e2f91a592ffd3
