The mean length (rounded to 2 DP) of these 8 people's index finger is 5.83
<h3>What is the mean length (rounded to 2 DP) of these 8 people's index finger?</h3>
The given parameters are:
<u>Children</u>
Mean = 5.6 cm
Frequency = 5
<u>Adult</u>
Mean = 6.2 cm
Frequency = 3
The mean length of these 8 people's index finger is calculated as:
So, we have
Mean = (5.6 * 5 + 6.2 * 3)/(5 + 3)
Evaluate
Mean = 5.83
Hence, the mean length (rounded to 2 DP) of these 8 people's index finger is 5.83
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Answer:
12
Step-by-step explanation:
The least common multiple of {6,8,12} is 24. This can be intuitively figured by noting that any multiple of 12 is a multiple of 6 and that 12 is 1.5x larger than 8. That means we only have so multiple 12 by 2 and 8 by 3 for them to be equal. The GCF of {20,42,72} is 2 as the prime factorization of 20 is 2x2x5 and 42 is 2x3x7. That means even without having to check 72 (which is clearly even so 2 is a factor), we know that 2 is the greatest common factor that they could share. So X/Y = 24/2 = 12
Answer:
h = 
- r
Step-by-step explanation:
The question requires you to make h the subject of the formula.
S = 2πrh + 2πr²
subtract 2πr² on both sides.
S - 2πr² = 2πrh - 2πr² - 2πr²
S - 2πr² = 2πrh
Dividing both sides by 2πr
(S - 2πr²)/2πr = 2πrh/ 2πr
h = - r
