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ElenaW [278]
2 years ago
13

Write the quadratic equation in standard form:

Mathematics
1 answer:
andreev551 [17]2 years ago
7 0
  • 5x²+7+3x=-3x

Standard form ax²+bx+c=0

  • 5x²+7+3x+3x=0
  • 5x²+7+6x=0
  • 5x²+6x+7=0

Done

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Area of circle <br> sector and finding the percentage
mestny [16]

Answer:2592/25

Step-by-step explanation: Big circle is pi*r^2= (4+3+3)^2*pi =314.15 minus 4^2*pi=50.26 equals 263.89. the big circle minus the first 2 layers of the circle = the outer circle. 314.15-(4+3)^2*pi=160.21 263.89-160.21=2592/25

4 0
4 years ago
Some fireworks are fired vertically into the air from the ground at an initial speed of 80 feet per second. The equation for thi
EastWind [94]

Answer:

Vertex (-2.5,-300)

Step-by-step explanation:

We are given with h(t)=-16 t^2 +80 t.  We are asked to find the vertex.

X-coordinate of vertex =\frac{-b}{2a}

Where 'a' is coefficient of t^{2} term

'b' is coefficient of 't' term.

From given function, a= -16

b=80

So,

x-coordinate of vertex =\frac{-80}{2(-16)}

                                =-2.5

y-coordinate of vertex =-16(-2.5)^{2} +80(-2.5)

Simplify it,

            =-100 -200

           = -300

So, vertex is at (-2.5, -300).

4 0
3 years ago
Y = 3x do this fast plz
mash [69]

Answer:

Step-by-step explanation:

3 0
3 years ago
Find the side of a square whose diagonal is of the given measure.<br> Given = 15.2 cm
Neko [114]

Answer:

15cm

Step-by-step explanation:

First, a square's diagonal is basically the hypotenuse of a 45-45-90 triangle. a 45-45-90 triangle has a really special relationship, where the side length is x, and the diagonal is x \sqrt{2}. So, the side length is 15.

8 0
3 years ago
Read 2 more answers
Right triangles abc and dbc with right angle c are given below. If cos(a)=15,ab=12 and cd=2, find the length of bd.
dmitriy555 [2]

see the attached figure to better understand the problem

we have that

cos(A)=\frac{1}{5} \\ AB=12\ units\\ CD=2\ units

Step 1

<u>Find the value of AC</u>

we know that

in the right triangle ABC

cos (A)=(AC/AB)\\AC=AB*cos(A)

substitute the values in the formula

AC=12*(1/5)\\ AC=2.4\ units

Step 2

<u>Find the value of BC</u>

we know that

in the right triangle ABC

Applying the Pythagorean Theorem

AB^{2} =AC^{2}+BC^{2}\\ BC^{2}=AB^{2} -AC^{2}

substitute the values

BC^{2}=12^{2} -2.4^{2}\\BC^{2}= 138.24\\ BC=11.76\ units

Step 3  

<u>Find the value of BD</u>

we know that

in the right triangle BCD

Applying the Pythagorean Theorem

BD^{2} =DC^{2}+BC^{2}

substitute the values  

BD^{2} =2^{2}+11.76^{2}

BD=11.93\ units

therefore

<u>the answer is</u>

the length of BD is 11.93 units

8 0
3 years ago
Read 2 more answers
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