Imagine the center of the Singapore Flyer ferris wheel is located at (0, 0) on a coordinate grid, and the radius lies on the x-a

Question

3 years ago

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Imagine the center of the Singapore Flyer ferris wheel is located at (0, 0) on a coordinate grid, and the radius lies on the x-a

xis. Write an equation of a circle for your ferris wheel, and sketch an image of what your ferris wheel would look like on the grid. Now graph a circle that is similar to the Ferris Wheel. Discuss the transformations needed to show that both circles on your graph are similar.

Mathematics

1 answer:

Nataly_w [17] · Answer 1 · 2022-12-14T02:17:38+03:00

The equation of the Ferris wheel is x² + y² = 25, and the transformation that shows that the circles are similar is the dilation transformation

<h3>How to determine the equation of the Ferris wheel?</h3>

From the question, we have the following parameters:

Center (a,b) = (0,0)

Radius, r = 5

The equation of a circle is represented as:

(x - a)² + (y - b)² = r²

So, we have:

(x - 0)² + (y - 0)² = 5²

Evaluate

x² + y² = 25

Hence, the equation of the Ferris wheel is x² + y² = 25

See attachment for the image of the Ferris wheel

Transformation to a similar circle

Assume that the similar circle has the following parameters:

Center (a,b) = (0,0)

Radius, r = 10

The equation of the circle would be:

(x - 0)² + (y - 0)² = 10²

Evaluate

x² + y² = 100

Since both circles have the same center, the transformation that shows that they are similar is the dilation transformation