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2 years ago

Write down two different expressions that are equivalent to 5x + 2 – 4y.

Mathematics

1 answer:

soldi70 [24.7K]2 years ago

6 0

Answer:

2 + 5x - 4y

-4y + 5x + 2

Step-by-step explanation:

The order of arrangement doesn't matter, what matters are the signs

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Consider the equations y=1/√x and y=x-2. The system of equations is equal at approximately

Ierofanga [76]

Set them equal or graph.
x= 2.618

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4 years ago

4x-5y=-15 <br> 7x-2y=21 <br> X=<br> Y=

Helen [10]

Answer:

The values of x and y to the given equations are x=5 and y=7

Step-by-step explanation:

Given equations are $4x-5y=-15\hfill (1)$

$7x-2y=21\hfill (2)$

To solve the given equations by elimination method :

Multiply the equation (1) into 2 we get

$8x-10y=-30\hfill (3)$

Multiply the equation (2) into 5 we get

$35x-10y=105\hfill (4)$

Now subtracting the equations (3) and (4) we get

$8x-10y=-30$

$35x-10y=105$

_________________

$-27x=-135$

$x=\frac{135}{27}$

Therefore x=5

Now substitute the value of x=5 in equation (1) we get

4(5)-5y=-15

20-5y=-15

-5y=-15-20

-5y=-35

$y=\frac{35}{5}$

Therefore y=7

The values are x=5 and y=7

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3 years ago

An envelope is 60 centimeters wide. About how many inches wide is the envelope? (1 inch ≈ 2.5 centimeters)

Dima020 [189]

Answer:

60/2.5 = 24 cm

Step-by-step explanation:

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3 years ago

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you and a friend fill balloons with water. Two out of every 25 balloons pop while being fillied what percent of the balloons do

kirill [66]

Answer:

92 percent

Step-by-step explanation:

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3 years ago

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Past records indicate that the probability of online retail orders

Tcecarenko [31]

Answer:

a) Mean = 1.6, standard deviation = 1.21

b) 18.87% probability that zero online retail orders will turn out to be fraudulent.

c) 32.82% probability that one online retail order will turn out to be fraudulent.

d) 48.31% probability that two or more online retail orders will turn out to be fraudulent.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The mean of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

In this problem, we have that:

$p = 0.08, n = 20$

a. What are the mean and standard deviation of the number of online retail orders that turn out to be fraudulent?

Mean

$E(X) = np = 20*0.08 = 1.6$

Standard deviation

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{20*0.08*0.92} = 1.21$

b. What is the probability that zero online retail orders will turn out to be fraudulent?

This is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{20,0}.(0.08)^{0}.(0.92)^{20} = 0.1887$

18.87% probability that zero online retail orders will turn out to be fraudulent.

c. What is the probability that one online retail order will turn out to be fraudulent?

This is P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{20,1}.(0.08)^{1}.(0.92)^{19} = 0.3282$

32.82% probability that one online retail order will turn out to be fraudulent.

d. What is the probability that two or more online retail orders will turn out to be fraudulent?

Either one or less is fraudulent, or two or more are. The sum of the probabilities of these events is decimal 1. So

$P(X \leq 1) + P(X \geq 2) = 1$

We want $P(X \geq 2)$

$P(X \geq 2) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

From itens b and c

$P(X \leq 1) = 0.1887 + 0.3282 = 0.5169$

$P(X \geq 2) = 1 - P(X \leq 1) = 1 - 0.5169 = 0.4831$

48.31% probability that two or more online retail orders will turn out to be fraudulent.

4 0

4 years ago