3 years ago

LAST ATTEMPT! MARKING AS BRAINLIEST! PLEASE Algebra topic is on logarithms

Mathematics

1 answer:

xenn [34]3 years ago

3 0

Answer:

Step-by-step explanation:

Not entirely sure about the first one, but I'll try the others:

2- log base 8 (8x) = log base 8 (8) + log base 8 (x) = 1 + log base 8 (x)

3 - log base 3 (5^x) = x log base 3 (5)

4 - log base 2 (5/x) = log base 2 (5) - log base 2 (x) = In 5 - In x

5 - log base 2 (2^x) = x log base 2 (2) = x · 1 = x

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Devon worked for Mr.greene on four days last week.He was paid a total of $120 for the four days of work. If he worked 2 hours ea

sammy [17]

It'll be 60 if you divided there is your actually answer

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3 years ago

What is the difference x + 5/ x + 2 - x + 1 /x^2 + 2x

xxTIMURxx [149]

2x^3 + 2x^2 + 5x + 1/ x^2

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4 years ago

Read 2 more answers

Use the value of the first integral I to evaluate the two given integrals. I = integral^3_0 (x^3 - 4x)dx = 9/4 A. integral^3_0 (

Troyanec [42]

Answer:

A) -9/2

B) 9/4

C) -9/2, same as A)

Step-by-step explanation:

We are given that $I=\int_0^3 x^3-4x dx=9/4$ . We use the properties of integrals to write the new integrals in terms of I.

A) $\int_0^3 8x-2x^3 dx=\int_0^3 -2(x^3-4x) dx=-2\int_0^3 x^3-4x dx=-2I=-9/2$ . We have used that ∫cf dx=c∫f dx.

B) $\int_3^0 4x - x^3 dx=-\int_0^3 (4x-x^3) dx=\int_0^3-(4x-x^3) dx=\int_0^3 x^3-4x dx=I=9/4$ . Here we used that reversing the limits of integration changes the sign of the integral.

C) It's the same integral in A)

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3 years ago

-(q + 14)= -3 + (-14)

Liula [17]

-(q + 14) = -3 + (-14)
-q - 14 = -3 -14
-q - 14 = -11
-q = +14 - 11
-q= 3

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3 years ago

Jim is baking and she at 1/4 cups of water twice then she added ½ couple for how much liquid is she put in the cake

Mashcka [7]

Answer:

1 cup

Step-by-step explanation:

Total

= 1/4(2) + 1/2

= 1/2 + 1/2

= 1 cup

Hope it helps.

;)

<3

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2 years ago