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Anna35 [415]
4 years ago
6

Multiply this expression and check:(4y^3+4y^2+8)(6y-4)

Mathematics
1 answer:
emmasim [6.3K]4 years ago
7 0
(4y³ + 4y²+8)(6y - 4)

Simplify.

24y⁴ - 16y³ + 24y³ - 16y² + 48y - 32

Add like terms.

24y⁴ + (-16y³ + 24y³) -16y² + 48 - 32

Simplify.

24y⁴ + 8y³ - 16y³ + 16

~Hope I helped!~
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if someone apply to 5 different colleges and 4 different majors how many different scenarios are there
svetoff [14.1K]

Answer:

He can apply for 4 different majors at each college giving

5 * 4 = 20     (if the college permits more than 1 application for a major)

4 0
3 years ago
A researcher was interested in seeing how many names a class of 38 students could remember after playing a name game After playi
Andreas93 [3]

Answer:

Proportion of the students recalled more than 15 names is 91.77%.

Step-by-step explanation:

We are given that a researcher was interested in seeing how many names a class of 38 students could remember after playing a name game After playing the name game, the students were asked to recall as many first names of fellow students as possible.

The mean number of names recalled was 19.41 with a standard deviation of 3.17.

<em>Let X = number of names recalled</em>

SO, X ~ N(\mu = 19.41,\sigma^{2} = 3.17^{2})

The z-score probability distribution is given by ;

                  Z = \frac{X-\mu}{\sigma} } } ~ N(0,1)

where, \mu = mean number of names recalled = 19.41

            \sigma = standard deviation = 3.17

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, proportion of the students recalled more than 15 names is given by = P(X > 15 names)

     P(X > 15) = P( \frac{X-\mu}{{\sigma} } } > \frac{15-19.41}{3.17}  } ) = P(Z > -1.39)

                                                      = P(Z < 1.39) = 0.9177  {using z table}

<em>Therefore, proportion of the students recalled more than 15 names is </em><em>91.77%.</em>

4 0
3 years ago
Bow is running a concession stand at a baseball game. He is selling nachos and water. Each other nachos cost $2.00, and a bottle
labwork [276]

The Solution:

From the graph, there is a point of intersection between the graphs of the two equations in the system. This implies that:

There is a viable solution to the given system of equations at the point where the two lines intersect, that is, at the point (26,34).

So, the correct answer is [option 3]

7 0
1 year ago
HELP I NEVER LEARND WITH BLOcKS IN ALGEBRA
NISA [10]

Answer:

I need to see the rest of the choices to be able to make a valid decision.

Step-by-step explanation:

I will update this as soon you edit the question

6 0
3 years ago
Read 2 more answers
Solve question 13. And 14. Please!! Will reward brainliest!!
SIZIF [17.4K]

Answer:

y = 4 sin( 0.5t - \frac{4\pi }{3} ) - 2

y = a sin ( 2t - \frac{-\pi }{3}) + 2

Step-by-step explanation:

In the first question,

amplitude = 4

Period = 4\pi

phase shift = \frac{-4\pi }{3}

Vertical shift = -2

Angular velocity , w = \frac{2\pi }{time period}

Here, w = \frac{2\pi }{4\pi } = 0.5

The general equation of a wave is

y = a sin( wt + ∅ )

Putting above values in the equation,

y = 4 sin( 0.5t - \frac{4\pi }{3} ) - 2

In the second question,

Amplitude is not given so we will take it as a.

time period = \pi

w = 2

Phase shift = \frac{-\pi }{3}

Vertical shift = 2

The equation is

y = a sin ( 2t - \frac{-\pi }{3}) + 2

5 0
3 years ago
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