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likoan [24]
2 years ago
6

In each room shown, you plan to put down carpet and add a wallpaper border around the ceiling. Which room needs more carpeting?

more wallpaper?
Room A or B needs more carpeting.
Room A or B needs more wallpaper.

Mathematics
1 answer:
gizmo_the_mogwai [7]2 years ago
6 0

Answer:

See below ~

Step-by-step explanation:

<u>Room A</u>

  • Area (carpeting) = 10 × 11 + 6 × 4 = 110 + 24 = 134 ft²
  • Perimeter (wallpaper) = 10 + 2(11) + 2(4) + 6 = 16 + 22 + 8 = 46 ft

<u>Room B</u>

  • Area (carpeting) = 12 × 8 + 1/2 × 3.14 × 6² = 96 + 3.14 × 18 = 96 + 56.52 = 152.52 ft²
  • Perimeter (wallpaper) = 12 + 2(8) + 3.14 × 6 = 28 + 18.84 = 46.84 ft

Room <u>A</u> needs more carpeting.

Room <u>A</u> needs more wallpaper.

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A room has 9 tables with 6 chairs each and 7 tables
Scilla [17]

Answer:

110 chairs.

Step-by-step explanation:

(9x6) +  (8x7)    First multiply 9x6 and 8x7.

(54) + (56)    In the first parenthesis, we have 9 tables with 6 chairs each. We are going to add that to the second parenthesis with 7 tables and 8 chairs each.

= 110    There are 110 chairs.

7 0
3 years ago
The initial size of the population is 300. After 1 day the population has grown to 800. Estimate the population after 6 days. (R
Cloud [144]

Solution :

Given initial population = 300

Final population after 1 day = 800

Number of days = 6

∴ $\frac{dP}{dt} =kt^{1/2} $

P(0) = 300    P(1) = 300

We need to find P(8).

$dP = kt^{1/2} dt$

$ \int 1 dP = \int kt^{1/2} dt$

$P(t) = k \left(\frac{t^{3/2}}{3/2}\right)+c$

$P(t)= \frac{2k}{3}t^{3/2} + c$

When P(0) = 300

$300 = \frac{2k}{3} (0)^{3/2} + c$

∴ c = 300

∴ $P(t)= \frac{2k}{3}t^{3/2} + 300$

When P(1) = 800

$800 = \frac{2k}{3} (1)^{3/2} + 300$

$500 = \frac{2k}{3}$

∴ k = 750

$P(t)= 500t^{3/2} + 300$

So, P(8) is

$P(t)= 500(8)^{3/2} + 300$

        = 11,614

So the population becomes 11,614 after 8 days.

8 0
3 years ago
Use the substitution method to solve the system of equations: <br><br> 2x – 5y = –14<br> x – 2y = –5
Nutka1998 [239]
Solve for 1 variable
solve for x in second

add 2y to both sides
x=2y-5
sub 2y-5 for x in first equation
2(2y-5)-5y=-14
4y-10-5y=-14
-10-y=-14
add 10 to both sides
-y=-4
times -1
y=4

sub
x=2y-5
x=2(4)-5
x=8-5
x=3

x=3
y=4
(3,4)
8 0
3 years ago
Read 2 more answers
Given right triangle MNL, what is the value of cos(M)? Three-fifths Three-fourths Four-fifths Five-thirds
lidiya [134]

By applying the Pythagorean Theorem and the Trigonometry ratio, CAH, the value of cos(M) = 4/5

<em><u>Recall:</u></em>

Trigonometry ratios, <em>SOH CAH TOA</em> can be applied to solve a right triangle.

  • Pythagorean Theorem can also be applied which is: c² = b² + a², where c is the longest side (hypotenuse length).

<em><u>Given:</u></em>

ΔMNL is a right triangle

ML = 25

NL = 15

Find MN using the Pythagorean Theorem:

MN = √(ML² - NL²)

MN = √(25² - 15²)

MN = 20

To find the value of cos(M), apply the trigonometry ratio, CAH, which is:

cos ∅ = Adj/Hyp

  • Where,

∅ = M (reference angle)

Hypotenuse = ML = 25

Adjacent = MN = 20

  • Plug in the values:

cos(M) = 20/25

cos(M) = 4/5

Learn more about Trigonometry ratios on:

brainly.com/question/10417664

5 0
3 years ago
40
prohojiy [21]
The area of the trapezoid is 30

6 0
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