Answer:
double a;
double b;
double distance = Math.sqrt( (Math.pow(a, 2) + Math.pow(b, 2));
System.out.println("The distance is: " + distance);
Explanation:
The code snippet is written in Java.
First, variable a is declared as a type of double and variable b is also declared as a type of double.
The given formula for the distance is:
√(a² + b²)
So we use the inbuilt function of Java to calculate the power and the square root.
Math.sqrt is to find the square root and it returns a value of type double.
Math.pow is use to calculate the value of a² and b².
a² = Math.pow(a, 2)
b² = Math.pow(b, 2)
Then Math.sqrt is applied to the sum of Math.pow(a, 2) and Math.pow(b, 2), the value is assigned to distance of type double.
The value of distance is now displayed to the user:
System.out.println("The distance is: " + distance);
Answer:
#
P(R I Q) = P(RnQ) / P(Q) = 0.1 Therefore P(RnQ) = 0.1 X 0.35 = 0.035 (The intersection in the centre of a Venn Diagram)
P(RnQ') = 0.15 In a Venn Diagram this is R but excluding the centre intersection with Q. Therefore P(R) = P(RnQ') + P(RnQ) = 0.15 + 0.035 = 0.185
P(RUQ) = 0.15 + 0.035 + 0.315 = 0.5 so 0.5 must be outside the Venn Diagram circles.
Explanation:
hope this helps
Answer:
A.
Explanation:
This phenomenon best illustrates why intelligence tests need to be revised for predictive validity. The tests are taken initially and show high scores, then they are taken again and show even higher scores. This shows that the individuals are getting smarter. If the test continues to be taken without revision then the same results will continue since the individuals will continue to become smarter but the test will continue being the same. Therefore, becoming much easier for the participants every time. This ultimately leads to better and better scores.
Answer:
Get him to the vet right now
Explanation: that's poison to dogs.
The men's thick, wavy and unruly hair is hardest to comb out.
