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2 years ago

Find the median of the following data set. 14,24,35,37,43,35,45,24,29,41,45, 37,19,45,44

Mathematics

2 answers:

Mariulka [41]2 years ago

8 0

Answer:

37,43,35 should be the answer to your game

Tom [10]2 years ago

3 0

Answer: 24

Step-by-step explanation: First of all because the number of data is 15 numbers, you know don't have to divide. Cross out the 1st and last numbers until you get to one number. I got 24

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4x−4y=-2 and −9x−4y =-3 solve by adding please !!!

jeyben [28]

1. Add 4x back into -2, you now have -4y=-4x-2. Add +4 from y and now you are at y=-4x+2 and this is the answer!

2. Add -9x back into -3, you now have -4y=9x-3. Add +4 from y and now you are at y=9x-7 and this is your answer!!

I hope this helped! Brainliest? :) -Raven❤️

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2 years ago

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Nezavi [6.7K]

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3 years ago

Simplify. 8u+9v+3u−5v

musickatia [10]

Combine like terms
8u+3u= 11u
and
9v-5v= 4v
So the answer is 11u+4v

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3 years ago

Twelve cows produce 224,988 pounds of milk. Find the unit rate in pounds per cow.

12345 [234]

Well, if 224,988 pounds of milk is produced by 12 cows, if i divide 224,988 by 12 i get the pounds per 1 cow. Consider it set up in this ratio.

224,988pounds/12 cows = xpounds/1 cow

Then you would solve for x.

Helpful? =)

3 0

3 years ago

At a high school, students can choose between three art electives, four history electives, and five computer electives. Each stu

V125BC [204]

Answer:

$\frac{^3C_1\times ^4C_1}{^{12}C_2}$

Step-by-step explanation:

Given,

Art electives = 3,

History electives = 4,

Computer electives = 5,

Total number of electives = 3 + 4 + 5 = 12,

Since, if a student chooses an art elective and a history elective,

So, the total combination of choosing an art elective and a history elective = $^3C_1\times ^4C_1$

Also, the total combination of choosing any 2 subjects out of 12 subjects = $^{12}C_2$

Hence, the probability that a student chooses an art elective and a history elective = $\frac{\text{Total combination of choosing an art elective and a history}}{\text{ Total combination of choosing any 2 subjects}}$

$=\frac{^3C_1\times ^4C_1}{^{12}C_2}$

Which is the required expression.

3 0

3 years ago

Read 2 more answers