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1 year ago

Is X-1 a factor of x^5-1?

Mathematics

1 answer:

Musya8 [376]1 year ago

4 0

Answer: No

Explanation:

According to factor theorem, if f(x)=0 then x is a factor of the given function or equation.

As x-1 is a factor

We equate x-1=0

x=1

Substituting in x^5-1, we have 1^5-1 =1-1=0.

Hence, it's a factor.

When coming to x^5+1, it would become 1^5+1=1+1=2

So x-1 isn't a factor of x^5+1.

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What is the scale factor of the dilation?

wel

Answer:

Step-by-step explanation:

D(1 , 1) to D'(3, 3)

so x (1 x 3)= 3

y (1 x 3) = 3

SF = 3

D(1 , 5) to D'(3, 15)

so x (1 x 3)= 3

y (5 x 3 ) = 15

SF = 3

Same on coordinate points B to B' and C to C'

so SF = 3

4 0

2 years ago

Read 2 more answers

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sineoko [7]

Answer: linear

Step-by-step explanation:

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1 year ago

The equation x2 - 9 = 0 has real solution(s). DONE

Andru [333]

Answer:

{-3, 3}

Step-by-step explanation:

x^2 - 9 = 0 can be written in factored form as (x -3)(x + 3) = 0. Letting each factor equal zero separately and solving for x, we get x: {-3, 3}

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2 years ago

O terreno da fazenda de Eduardo foi aumentado 2 m na horizontal e 2 m na vertical. Se antes do aumento o terreno tinha o formato

Novay_Z [31]

Answer:

New area of Eduardo's farm after the increase = x² + 4x + 4

Nova área da fazenda de Eduardo após o aumento = x² + 4x + 4

Step-by-step explanation:

English Translation

The land on Eduardo's farm was increased by 2 m horizontally and 2 m vertically. If before the increase the land was shaped like an x-side square, what is the new area after the increases?

Solution

The previous area of Eduardo's farm is the are of a square with side lenght of x.

Area of a square = (side length)² = x²

Then, the land on Eduardo's farm was increased by 2 m horizontally and 2 m vertically.

New horizontal length of Eduardo's farm = (x+2)

New vertical length of Eduardo's farm = (x+2)

New area of Eduardo's farm = (x+2)(x+2)

= x² + 4x + 4

In Portugese/Em português

A área anterior da fazenda de Eduardo é a de um quadrado com comprimento lateral de x.

Área de um quadrado = (comprimento lateral)² = x²

Em seguida, o terreno da fazenda de Eduardo foi aumentado 2 m na horizontal e 2 m na vertical.

Novo comprimento horizontal da fazenda de Eduardo = (x + 2)

Novo comprimento vertical da fazenda de Eduardo = (x + 2)

Nova área da fazenda de Eduardo

= (x + 2) (x + 2) = x² + 4x + 4

Hope this Helps!!!

Espero que isto ajude!!!

7 0

3 years ago

A- 13 B- 130 C- 43 D- 10

Mumz [18]

7x + 9 + 3x + 4 = 143

10x = 143 - 9 - 4

10x = 130

x = 13/10

x = 13 answer

4 0

2 years ago