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2 years ago

I need help with math

Mathematics

1 answer:

nevsk [136]2 years ago

6 0

Answer:

Step-by-step explanation:

<h3>7) The lengths of the tangent from an external point to a circle are equal.</h3>

2x - 1 = x + 10

2x = x + 10 + 1

2x = x + 11

2x -x = 11

$\sf \boxed{\bf x = 11}$

8) Radius : XC

Chord: CB

Diameter : AB

Name of the circle: X {a circle is named by its center}

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Can someone help me with this problem??

Pavlova-9 [17]

Find the slope first by doing (6+2)/(4-3)=8/1 or just 8. Next use a set of coordinates into the equation so 6=8(4)+b then solve so 6=32+b next subtract 32 from both sides which would equal -24=b. Then plug it all into the equation so y=8x-24

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4 years ago

Jacob scored 85%, 90%, and 74% on his first three tests. Then he scored 99%, 84% and 75% on his next three

AlekseyPX

The average of the first three is 83 (85 + 90 + 74)/3
The average of the next 3 is 86.

The difference is 3

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3 years ago

50 Points, 5 stars, and Brainliest Answer for the BEST Answers! Your answers MUST be correct, and you must answer them ALL!

devlian [24]

#1:Proportional Medians Theorem

#2:BD/FH = CB/GF

#3: 24/16 27/x

So the first ratio is 3/2 because both are divisible by 8. the ratio stays 3/2. 3*9=27. so 2*9=18

x=18

#4: x = 8.5

#5: x = 68

Hope this helps!!

6 0

3 years ago

The mean annual income for people in a certain city is 37 thousand dollars, with a standard deviation of 28 thousand dollars. A

Aloiza [94]

Answer:

$P( 31 < \bar X< 41)$

And we can ue the z score formula given by:

$z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And using this formula we got for the limits:

$z = \frac{31-37}{\frac{28}{\sqrt{50}}}= -1.515$

$z = \frac{41-37}{\frac{28}{\sqrt{50}}}= 1.01$

So we want to find this probability:

$P(-1.515$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the annual income of a population, and for this case we know the following info:

$\mu=37$ and $\sigma=28$ and we are omitting the zeros from the thousand to simplify calculations

We select a sample size of n=50>30.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by: