Answer:
<em><u>-10</u></em>
Step-by-step explanation:
Alright, let me explain negative multiplcation.
A negative number multiplied by another negative number becomes a positive number. But a negative number multiplied by a positive number is still negative. <u>Every pair of 2 negatives become positive.</u> This is important. Make sure to remember that.
That's it! If you need more help then reach out to your teacher. I'm sure that they will be more than happy to help!
Hope this helped! :)
Answer:
u = 12
Step-by-step explanation:
The equation is showing 5(u) = 60
<u>Begin: 5(u)= 60</u>
2. Divide the 5 from both sides to get the u-value alone.
a) 5u/5 = u b) 60/5 = 12
<u>Now: u = 12</u>
If you ever have a polynomial with a solution of bi, then it will also have a solution of -bi. Imaginary solutions always come in pairs.
So, yes, you could have a polynomial with solutions 2i and 5i, as long as -2i and -5i are also solutions.
(x-2i)(x+2i)(x-5i)(x+5i) would be the most basic polynomial you could form.
(x-2i)(x+2i)(x-5i)(x+5i) = (x^2+4)(x^2+25)
= x^4 + 29x^2 + 100
So the equation would be x^4 + 29x^2 + 100 = 0.
Now, if the question was "only the solutions of 2i and 5i and no others," then the answer is no, for the previously stated reason.
Answer:
Answer is -759/5
Step-by-step explanation:
To find the sum of a finite geometric series, use the formula,
Sn= a1-a1r^n/ 1-r
where n is the number of terms, a1 is the first term and r is the common ratio .
common ratio = a2/a1
S8=3-3(-2/3)8 / 1-(-2/3)
S8 = 3-(-2)8/ 1+ 2/3
S8= 3-256/ 3+2/3
S8= -253/5/3
S8= -253*3/5
S8= -759/5
It looks like you're asking to solve for the coefficients such that
Expanding the right side gives
The coefficients on both sides must be equal, so
Solving the system yields .