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Korolek [52]
2 years ago
15

Please help im having so much trouble with this problem: Simplify square root of five times the quantity six minus four square r

oot of three.
9
thirty square root of three
six square root of five minus four square root of fifteen
square root of thirty minus twenty square root of three
Mathematics
1 answer:
Monica [59]2 years ago
3 0

Answer:  six square root of five minus four square root of fifteen

In symbolic form the answer looks like \boldsymbol{6\sqrt{5} -4 \sqrt{15}}

==========================================================

Work Shown:

\sqrt{5}\left(6 - 4\sqrt{3}\right)\\\\\sqrt{5}\left(6\right) + \sqrt{5}\left(-4\sqrt{3}\right)\\\\6\sqrt{5} -4 \sqrt{5*3}\\\\6\sqrt{5} -4 \sqrt{15}\\\\

The basic idea is to distribute the outer term \sqrt{5} to each term inside. From there you simplify.

For the second to last step, I used the rule that \sqrt{A}*\sqrt{B} = \sqrt{A*B}

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