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miss Akunina [59]
2 years ago
9

A right triangle has side lengths 216 millimeters, 405 millimeters, and 459 millimeters. What are the lengths of the legs and wh

y?
Mathematics
1 answer:
Artemon [7]2 years ago
8 0
I put 25 for quiz question 1
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What is the surface area?
Ratling [72]
The formula for the surface area of a rectangular prism is

A= 2(wl+hl+hw)

We are given the height =2cm, width= 5cm, and length= 10cm. All you have to do is plug this info in!

A= 2(wl+hl+hw)
= 2[(5)(10)+(2)(10)+(2)(5)]
= 2(50+20+10)
= 2(80)
=160 cm squared

Hope this helps!! :)
4 0
3 years ago
Choose an angle or point from the preimage and name its image
Ksenya-84 [330]

From the preimage, the angle or point I choose is P and I name its image as: P maps to P’.

 

The set of all elements of the domain that map to the members of S is the inverse image or preimage of a particular subset S of the codomain of a function.

4 0
3 years ago
I need help pls!!!!!!!!
KATRIN_1 [288]
The y-intercept is -7
4 0
3 years ago
The sum of two numbers is 54. The large number is 18 more than the sampler number. What are the numbers ?
Karolina [17]

Answer: a=36; b=18


Step-by-step explanation:

1. You know that the sum of two numbers is 54, then, you have:

a+b=54

2. According to the problem, the larger number is 18 more than the sampler number, this can be expressed as following:

a=b+18

3. Then, you must substitute the second equation into the first equation and solve for b:

b+18+b=54

b=18

4. Then the value of a is:

a+18=55

a=36



7 0
3 years ago
Find the equation of the line that passes through the point of intersection of x + 2y = 9 and 4x -2y = -4 and the point of inter
Rudik [331]

Answer:

y=-6x+10

Step-by-step explanation:

The point of intersection of

x+2y=9...eqn1


and


4x-2y=-4...eqn2

is the solution of the two equations.


We add equation (1) and equation(2) to get,

x+4x+2y-2y=9+-4


\Rightarrow 5x=5


\Rightarrow x=1

We put x=1 into equation (1) to get,

1+2y=9

\Rightarrow 2y=9-1

\Rightarrow 2y=8

\Rightarrow y=4


Therefore the line passes through the point, (1,4).


The line also passes through the point of intersection of

3x-4y=14...eqn(3)

and

3x+7y=-8...eqn(4)

We subtract equation (3) from equation (4) to obtain,

3x-3x+7y--4y=-8-14


\Rightarrow 11y=-22

\Rightarrow y=-2


We substitute this value into equation (4) to get,

3x+7(-2)=-8


3x-14=-8


3x=-8+14


3x=6

x=2

The line also passes through

(2,-2)



The slope of the line is

slope=\frac{4--2}{1-2} =\frac{6}{-1}=-6


The equation of the line is

y+2=-6(x-2)

y+2=-6x+12


y=-6x+10 is the required equation





4 0
3 years ago
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