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Fed [463]
2 years ago
7

What is the product? startfraction x squared minus 16 over 2 x 8 endfraction times startfraction x cubed minus 2 x squared x ove

r x squared 3 x minus 4 endfraction
Mathematics
1 answer:
melamori03 [73]2 years ago
4 0

The product of the given expression is \frac{x(x-1)(x-4)}{2(x+4)} OR \frac{x(x^{2} -5x+4)}{2x+8} OR \frac{x^{3} -5x^{2} +4x}{2x+8}

<h3>Simplifying fractions </h3>

From the question, we are to determine the product of the given expressions

The given expressions are

\frac{x^{2} - 16}{2x+8}\times \frac{x^{3}-2x^{2} +x}{x^{2} +3x-4}

\frac{(x+4)(x-4)}{2(x+4)}\times \frac{(x^{2} -x)(x-1)}{(x-1)(x+4)}

\frac{(x-4)}{2}\times \frac{(x^{2} -x)}{(x+4)}
\frac{(x-4)}{2}\times \frac{x(x-1)}{(x+4)}

\frac{x(x-1)(x-4)}{2(x+4)}

OR

\frac{x(x^{2} -5x+4)}{2x+8}

OR
\frac{x^{3} -5x^{2} +4x}{2x+8}

Hence, the product of the given expression is \frac{x(x-1)(x-4)}{2(x+4)} OR \frac{x(x^{2} -5x+4)}{2x+8} OR \frac{x^{3} -5x^{2} +4x}{2x+8}

Learn more on Simplifying fractions here: brainly.com/question/27038950

Here is the complete and correct question:

What is the product? StartFraction x squared minus 16 Over 2 x + 8 EndFraction times StartFraction x cubed minus 2 x squared + x Over x squared + 3 x minus 4 EndFraction

#SPJ4

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Slope-intercept form:  starting with y = mx + b, substit. -6 for x, 6 for y and -1/3 for m:

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107810

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You can use the order of operations! So we start with 99^3/9. That is 99^2*11. So now let’s do 99/99, it’s 1. So 99^2*11 is 107811, so the answer is 107810.

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A The length of a rectangle is 4 m more
Lady bird [3.3K]

Given :

  • The length of a rectangle is 4m more than the width.
  • The area of the rectangle is 45m²

⠀

To Find :

  • The length and width of the rectangle.

⠀

Solution :

We know that,

\qquad { \pmb{ \bf{Length \times Width = Area_{(rectangle)}}}}\:

So,

Let's assume the length of the rectangle as x and the width will be (x – 4).

⠀

Now, Substituting the given values in the formula :

\qquad \sf \: { \dashrightarrow x  \times  (x - 4) = 45 }

\qquad \sf \: { \dashrightarrow {x}^{2}  - 4x = 45 }

\qquad \sf \: { \dashrightarrow {x}^{2}  - 4x - 45 = 0 }

\qquad \sf \: { \dashrightarrow {x}^{2}    - 9x+ 5 x - 45 = 0 }

\qquad \sf \: { \dashrightarrow x(x - 9) + 5(x - 9) = 0 }

\qquad \sf \: { \dashrightarrow (x  - 9) (x  + 5) = 0 }

\qquad \sf \: { \dashrightarrow x = 9, \: \: x =  - 5}

⠀

Since, The length can't be negative, so the length will be 9 which is positive.

⠀

\qquad { \pmb{ \bf{ Length _{(rectangle)} = 9\:m}}}\:

\qquad { \pmb{ \bf{ Width _{(rectangle)} = 9 - 4=5\: m}}}\:

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8 0
2 years ago
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