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Goshia [24]
2 years ago
14

Jen traveled from Boston to cape cod at 60mph. On her way back, The traffic was bad and her return trip took 3 times as long. Wh

at is her averge speed
Please help will mark brainlest
Mathematics
1 answer:
crimeas [40]2 years ago
6 0

The average speed of Jen for the entire journey is 30 mph.

<h3>Average speed</h3>

The average speed of a journey is the ratio of total distance to total time of motion.

Total time of motion = 3 + 9 = 12 hours

Total distance = 2[3(60)] = 2(180 miles) = 360 miles

Average speed = 360 /12

Average speed = 30 miles per hour

Thus, the average speed of Jen for the entire journey is 30 mph.

Learn more about average speed here: brainly.com/question/6504879

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Step-by-step explanation:

-4/5-1/3

-4/5+-1/3

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Find the SUm of the infinite series.
givi [52]

I'll do problem 13 to get you started.

The expression 4\left(\frac{2^n}{7^n}\right) is the same as 4\left(\frac{2}{7}\right)^n

Then we can do a bit of algebra like so to change that n into n-1

4\left(\frac{2}{7}\right)^n\\\\4\left(\frac{2}{7}\right)^n*1\\\\4\left(\frac{2}{7}\right)^n*\left(\frac{2}{7}\right)^{0}\\\\4\left(\frac{2}{7}\right)^n*\left(\frac{2}{7}\right)^{1-1}\\\\4\left(\frac{2}{7}\right)^n*\left(\frac{2}{7}\right)^{1}*\left(\frac{2}{7}\right)^{-1}\\\\4*\left(\frac{2}{7}\right)^{1}\left(\frac{2}{7}\right)^n*\left(\frac{2}{7}\right)^{-1}\\\\\frac{8}{7}\left(\frac{2}{7}\right)^{n-1}\\\\

This is so we can get the expression in a(r)^(n-1) form

  • a = 8/7 is the first term of the geometric sequence
  • r = 2/7 is the common ratio

Note that -1 < 2/7 < 1, which satisfies the condition that -1 < r < 1. This means the infinite sum converges to some single finite value (rather than diverge to positive or negative infinity).

We'll plug those a and r values into the infinite geometric sum formula below

S = a/(1-r)

S = (8/7)/(1 - 2/7)

S = (8/7)/(5/7)

S = (8/7)*(7/5)

S = 8/5

S = 1.6

------------------------

Answer in fraction form = 8/5

Answer in decimal form = 1.6

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