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guapka [62]
2 years ago
9

The area of the triangle formed by points of intersection of parabola y=a(x-3)(x+2)

SAT
1 answer:
juin [17]2 years ago
6 0

It is to be noted that the Area of the Triangle formed by the points of intersection of the Parabola derived from the equation y = a(x-3) (x+2) with the derived coordinates is 12.

<h3>What is a Parabola?</h3>

In mathematics, a parabola is a symmetrical open plane curve generated when a cone meets a plane parallel to its side.

Under the influence of gravity, a projectile's journey follows a curve of this shape.

Solution:

Step I - recall that y=a(x-3)(x+2)

This means that the base of the triangle is: 3-(-2) = 5

It's Height is = 6a. We arrive at this value when we make x = 0 and utilize the absolute value of the derivation.

Given that the area of a triangle is:

y=a(x-3)(x+2), we therefore have the following equation:

12 = 1/2 * 5 * 6 * A

If A = 4/5, then the solution to our equation comes to 12.

Learn more about Parabola at:
brainly.com/question/64712

#SPJ1

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<h3>How to calculate the volume of a cylinder?</h3>

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