The area of the triangle formed by points of intersection of parabola y=a(x-3)(x+2)
1 answer:
It is to be noted that the Area of the Triangle formed by the points of intersection of the Parabola derived from the equation y = a(x-3) (x+2) with the derived coordinates is 12.
<h3>What is a Parabola?</h3>
In mathematics, a parabola is a symmetrical open plane curve generated when a cone meets a plane parallel to its side.
Under the influence of gravity, a projectile's journey follows a curve of this shape.
Solution:
Step I - recall that y=a(x-3)(x+2)
This means that the base of the triangle is: 3-(-2) = 5
It's Height is = 6a. We arrive at this value when we make x = 0 and utilize the absolute value of the derivation.
Given that the area of a triangle is:
y=a(x-3)(x+2), we therefore have the following equation:
12 = 1/2 * 5 * 6 * A
If A = 4/5, then the solution to our equation comes to 12.
Learn more about Parabola at:
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Based on the calculations, the value of x and y in this equation are both equal to 5.
<h3>What is a system of linear equations?</h3>A system of linear equations can be defined as an algebraic equation of the first order that has two (2) variables with each of its term having an exponent of one (1).
<u>Given the following data:</u>
x + y = 10 .....equation 1.
x = 5. .....equation 2.
<h3>How to evaluate an equation.</h3>In order to evaluate the given mathematical equation, we would substitute equation 2 into equation 1 as follows:
y = 5.
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