The base of a ladder is placed 2.8m away from a tree that is 4.5m tall. The end of the ladder touches the top of the tree. Calcu
1 answer:
The length of the ladder is 5.3 meter if the base of a ladder is placed 2.8 m away from a tree that is 4.5 m tall. The end of the ladder touches the top of the tree.
<h3>What is a right-angle triangle?</h3>It is a triangle in which one of the angles is 90 degrees and the other two are sharp angles. The sides of a right-angled triangle are known as the hypotenuse, perpendicular, and base.
As per the picture attached, the triangle is a right angle triangle:
Let's assume the length of the ladder is x meter
From the Pythagoras theorem:
x = √(2.8²+4.5²)
x = √(7.84+20.25)
x = 5.3 m
Thus, the length of the ladder is 5.3 meter if the base of a ladder is placed 2.8 m away from a tree that is 4.5 m tall. The end of the ladder touches the top of the tree.
Learn more about the right angle triangle here:
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Answer:
so at the long run we can conclude that the best option is :
A) win 0.20 cents per play
Step-by-step explanation:
Previous concepts
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.
The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).
Solution to the problem
Let X the random variable who represent the ampunt of money win/loss at the game defined.
The probability of loss $3.00 for this game is 0.2 and the probability of win is 1-0.2=0.8 and you will recieve $1.00 if you win. The expected value is given by:
And for this case if we replace we got:
so at the long run we can conclude that the best option is :
A) win 0.20 cents per play