Answer:
Stems and root
Explanation:
Auxins facilitate stem elongation while inhibiting axillary bud formation, ensuring apical dominance. The root, branches, and stem and tip all contain them. Hydroxy Acetic Acid is a perfect example. Auxin is indeed a growth hormone that facilitates cell elongation and is formed in the stem tip.
The overexpression results in increased micro vessel density and lesion size in mice with induced endometriosis.
Endometriosis is a benign gynecological disorder.
- it's far characterized through the ectopic presence of endometrial glands and stroma out of doors of the uterine hollow space and is carefully related to dysmenorrhea, pelvic pain, and subfertility.
- In endometriosis, the involvement of vascular endothelial mobile growth issue (VEGF) and different angiogenic mediators has long been recognized endometriotic angiogenesis entails numerous pathways and the blockade of simply one single pathway won't effectively suppress Endometriosis
- Slit is a secretory glycoprotein which include 3 members, Slit1, Slit2, and Slit3, and become at first found to be secreted repellents in axon steerage and neuronal migration It has been shown to be an endogenously available inhibitor of leukocyte chemotaxis.
- receptor for Slit is the protein Roundabout (ROBO), which currently includes 4 members (ROBO1-4)
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Epidermal tissue as this is what makes up the lining
<span>The theory puts forward the concept that chloroplasts were developed from one form of prokaryotic organisms taken up inside a primordial eukaryotic cell. This is an organism form that uses light energy to divide, this part of its processes became the chloropplast whilst another formed the origin of mitochondria.</span>
Answer:
Explanation:
the purple allele (C) is dominant to the pink allele (c).
The frequency of C represents p while that of c represent q. Using the formula p+q= 1
The proportion of pink flower is 153/1000 = 0.153. This is also the frequency of the genotype cc (q^2).
Thud to find q which is the frequency of the c allele,
q = √0.153
q = 0.3912
From the formula p +q = 1 we can find p p = 1 - 0.3912
p which is the frequency of the C allele
p = 0.6088.
B. the proportion of all purple flowering plants that are heterozygotes and homozygotes is 847 / 1000 = 0.847
