(16x^1/6y^-2)^3/2 / (x^-1/6y^6)^3/2
=(4^2)^3/2 (x^1/6)^3/2 (y^-2)^3/2 / (x^-1/6)^3/2(y^6)^3/2
= 4^3 x^1/4 y^-3 / x^-1/4 y ^9
= 64 x^(1/4 +1/4) y^(-3-9)
= 64 x^1/2 y^-12
= 64 x^1/2 / y^12
answer is D.64 x^1/2 / y^12
What is it??? there is no paper attached
Answer:
i have no idea what to do
Step-by-step explanation:
<h3>Answer;</h3>
-Coplanar lines
A transversal must intersect two or more <u>coplanar</u> lines.
<h3>Explanation;</h3>
- Coplanar lines are lines that lie on the same plane.
- Examples of such lines include perpendicular lines, parallel line and any two straight lines that have a common point, such as the three edges of a triangle.
- A transversal cuts two or more parallel lines, which are coplanar, that is they lie on the same plane