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2 years ago

Point A lies on the circle and has an x-coordinate of 1..

Mathematics

1 answer:

Neko [114]2 years ago

6 0

Answer:

the last one

Step-by-step explanation:

because the distance/length formula is applied here so you just need to rearrange the coordinates in to the formula

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Look at jasmine’s picture frame.what is its perimeter

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7 + 7 + 5 + 5 (two sides are 7 and two sides are 5) = 24

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3 years ago

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Cathy is paid at a rate of K7.20 per hour for a basic hour-week of 70 hours. She is paid time-and-a-half for over-time during th

Levart [38]

Answer:

K1310.4

Step-by-step explanation:

Basic pay per hour = K7.20

Overtime pay during the week per hour = 1 1/2 * K7. 20 = K10.8

Weekends = 2 * K7.20 = K14.4

Basic hours per week = 70 hours

In a fortnight :

Basic hours = 70 * 2 = 140 hours :

Hence, Overtime during the week = (160 - 140) = 20 hours

Weekend hours = (4 +2) = 6 hours

Total earning :

(140 * 7.20) + (20 * 10.8) + (6 * 14.4)

1008 + 216 + 86.4

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3 years ago

Will give brainliest to the homie that gets it right! please help!

12345 [234]

I'm pretty sure the answer to your question is -3/5 + 4/5. C.

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3 years ago

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Es 18 de junio de 1815, las tropas napoleónicas se encuentran justo adelante, tu eres el ingeniero en balística y el general Wel

Airida [17]

Answer:

89.1° or -1.4°

Step-by-step explanation:

1. Location:

You are on the Mont-Saint-Jean escarpment, near the Belgian town of Waterloo.

The French troops are about 50 m below you and 1.2 km distant.

2. Finding the firing angle

Data:

R = 1200 m

u = 600 m/s

h = -50 m (the height of the target)

a = 9.8 m/s²

We have two conditions.

Horizontal distance

(1) 1200 = 600t cosθ

Vertical distance

(2) -50 = 600t sinθ - 4.9t²

Divide each side of (1) by 600cosθ.

$(3) \, t =\dfrac{2}{\cos \theta}$

Substitute (3) into (2)

$-50 = 600t \sin \theta - 4.9t^{2} = 600 \left( \dfrac{2}{\cos \theta} \right ) \sin \theta - 4.9 \left( \dfrac{2}{\cos \theta} \right )^{2}\\\\(4) \, -50 = 1200 \tan \theta - \dfrac{19.6}{\cos^{2} \theta}$

Recall that

(5) sec²θ = 1/cos²θ = tan²θ + 1

Substitute (5) into (4)

$-50 = 1200 \tan \theta - 19.6 \left(\tan^{2} \theta}+ 1\right )$

Set up a quadratic equation

$\begin{array}{rcl}-50 & = & 1200 \tan \theta - 19.6\tan^{2} \theta -19.6 \\0 & = & 1200 \tan \theta - 19.6\tan^{2} \theta + 30.4\\0 & =&19.6\tan^{2} \theta - 1200 \tan \theta - 30.4\\0 & =&\tan^{2} \theta - 61.224 \tan \theta - 1.551\\\end{array}$

Solve for θ

Use the quadratic formula.

tanθ = 61.249 or -0.025

θ = arctan(61.249) = 89.1° or

θ = arctan(-0.025) = -1.4°

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3 years ago

Which expression is equivalent to -2 (x +7) - 6x

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The answer is a (-8x+14)

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