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Radda [10]
3 years ago
14

If f(x) is an exponential function where f(2)=23 and f(3)=58, then find the value of f(6), to the nearest hundredth.

Mathematics
1 answer:
Stels [109]2 years ago
8 0

The exponential function is given as 3.68 × (2.52)ˣ. Then the value of function at x = 6 will be 942.43.

<h3>What is an exponent?</h3>

The exponent denotes that the base will rise to a specific level of strength. The base is X, and the power is n.

If f(x) is an exponential function where f(2) = 23 and f(3) = 58.

Then the exponential function will be

f(x) = abˣ

If f(2) = 23, then we have

23 = ab² ...1

If f(3) = 58, then we have

58 = ab³ ...2

Then from equations 1 and 2, we have

a = 3.62 and b = 2.52

Then the function will be

f(x) = 3.68 × (2.52)ˣ

Then the value of f(6) will be

f(6) = 3.68 × (2.52)⁶

f(6) = 3.68 × 256.1

f(6) = 942.43

More about the exponent link is given below.

brainly.com/question/5497425

#SPJ1

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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It would be easiest to do 48

But that's not exactly what the question is asking

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I wanted to show you the other way so you would be able to think of it in a different way which would be easier

You would just list out the multiples again.  

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Ok, I give up on that

Let's just do 16*18 which is 288.

288 is your LCM

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I hope this helped

Let me know if you have any questions

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