Haley wickenheiser felt angry after the Bach said the IOC would make a decision in the next month as the IOC says the games will be held no later than summer 2021 but they will still be called the 2020 Tokyo Olympics.
Explanation:
- The Tokyo Olympics were postponed until 2021 on Tuesday, ending weeks of speculation that the games could not go ahead as scheduled because of the coronavirus pandemic.
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The International Olympic Committee made the decision after speaking with Japanese Prime Minister Shinzo Abe and local organizers.
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The IOC said the games will be held not later than summer 2021 but they will still be called the 2020 Tokyo Olympics.
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“President Bach said he will agree ‘100%,’ and we agreed to hold the Tokyo Olympics and Paralympics in the summer of 2021 at the latest,” Abe said, saying holding the games next year would be “proof of a victory by human beings against the coronavirus infections.”
- The decision came only a few hours after local organizers said the torch relay would start as planned on Thursday.
Answer:
i have no clue sorry:(
Explanation:
I didn't do this to get points i promise
Answer:
See explaination
Explanation:
#include <fstream>
#include <iostream>
#include <iomanip>
using namespace std;
int main()
{
// Fill in the code to define payfile as an input file
ifstream payfile;
float gross;
float net;
float hours;
float payRate;
float stateTax;
float fedTax;
cout << fixed << setprecision(2) << showpoint;
// Fill in the code to open payfile and attach it to the physical file
// named payroll.dat
payfile.open("payroll.dat");
// Fill in code to write a conditional statement to check if payfile
// does not exist.
if(!payfile)
{
cout << "Error opening file. \n";
cout << "It may not exist where indicated" << endl;
return 1;
}
ofstream outfile("pay.out");
cout << "Payrate Hours Gross Pay Net Pay"
<< endl << endl;
outfile << "Payrate Hours Gross Pay Net Pay"
<< endl << endl;
// Fill in code to prime the read for the payfile file.
payfile >> hours;
// Fill in code to write a loop condition to run while payfile has more
// data to process.
while(!payfile.eof())
{
payfile >> payRate >> stateTax >> fedTax;
gross = payRate * hours;
net = gross - (gross * stateTax) - (gross * fedTax);
cout << payRate << setw(15) << hours << setw(12) << gross
<< setw(12) << net << endl;
outfile << payRate << setw(15) << hours << setw(12) << gross
<< setw(12) << net << endl;
payfile >> hours ;// Fill in the code to finish this with the appropriate
// variable to be input
}
payfile.close();
outfile.close();
return 0;
}
Answer:
Time Complexity of Problem - O(n)
Explanation:
When n= 1024 time taken is t. on a particular computer.
When computer is 8 times faster in same time t , n can be equal to 8192. It means on increasing processing speed input grows linearly.
When computer is 8 times slow then with same time t , n will be 128 which is (1/8)th time 1024.
It means with increase in processing speed by x factor time taken will decrease by (1/x) factor. Or input size can be increased by x times. This signifies that time taken by program grows linearly with input size n. Therefore time complexity of problem will be O(n).
If we double the speed of original machine then we can solve problems of size 2n in time t.
Answer:
general regulatory and speed control.
