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Leviafan [203]
3 years ago
12

Which is the graph of the function f(x)= negative square root x

Mathematics
1 answer:
Vsevolod [243]3 years ago
6 0
First, note that \sqrt{x} is always positive (except for x=0), so -\sqrt{x} must be always negative.

Thus, the only plausible graphs are 1 and 3 since they are below the x-axis.

Now, \sqrt{x} and -\sqrt{x} are only defined for x≥0, because only for these x'es we can take the square root. 

Note that the third graph has domain (-infinity, 0], so it is not the right one, while 1 is ok.


Answer: first graph  


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garri49 [273]
58 + 8 = 66 miles per hour
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3 years ago
Problem: (5x^4 – 3x^3 + 6x) – (3x^3 + 11x^2 – 8x)<br><br> Answer: 5x^4-6x^3 -11x^2 +14x
g100num [7]
Combine the like terms by adding the coefficients,
->5x^4 can't add anything so leave it there,
->-3x^3 can add -3x^3 which gives you -6x^3,
->We can't do anything with -11x^2 so leave it there as well,
->6x add to -(-8x) gives you 14x,
You will get for your final answer is 5x^4-6x^3-11x^2+14x.
8 0
3 years ago
Solve using the elimination method:<br> X-3y=7<br> 3x + 3y=9
sergij07 [2.7K]

Answer:

                        x=4\\\\y=-1

Step-by-step explanation:

Given Equation:

x-3y=7      Equation:1

3x + 3y=9     Equation:2

Dividing Equation:2 by '3' both the sides:

x+y=3      

or   x=3-y     Equation:3

Putting the vale of 'x' in Equation:1

                             x-3y=7

                          (3-y)-3y=7\\\\3-y-3y=7\\\\3-4y=7\\\\

Subtracting '3' both sides

                             -4y=7-3\\\\-4y=4

                                 y=\frac{4}{-4}

                                 y=-1

Putting value of 'y' in Equation:3

                                x=3-y

                                x=3-(-1)\\\\x=3+1\\\\x=4

The solution of the equations is :

                              x=4\\\\y=-1

7 0
3 years ago
3x-4y=16 slope and intercept form
elena55 [62]

Answer:

y=3/4x-4

Step-by-step explanation:

The form is y=mx+b so isolate y

-4y=16-3x

y=-16/4-3x/-4

y=3/4x-4

5 0
2 years ago
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The lines are parallel. Find the slope-intercept form of the equation y₂.
Bas_tet [7]
Since the lines are parallel and you know the slope of y_{1} is -2, you know the slope of line y_{2} will also be -2. You can see on the coordinate grid that line y_{2} crosses the y-axis at -1. When you piece all of these facts together into slope-intercept form you get y_{2} = -2x - 1.
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