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fredd [130]
2 years ago
10

What is the answer of 11 6/9 - 4 4/9

Mathematics
2 answers:
yaroslaw [1]2 years ago
8 0
<h3>given:</h3>

11 \frac{6}{9}  - 4 \frac{4}{9}

<h3>solution:</h3>

11 \frac{6}{9}  - 4 \frac{4}{9}

=  \frac{35}{3}  -  \frac{40}{9}

=  \frac{(35 \times 9)  - (40  \times 30)}{3 \times 9}

=  \frac{315 - 120}{27}

=  \frac{195}{27}

= 7 \frac{2}{9}

IrinaK [193]2 years ago
4 0

Answer:

7  \frac{2}{9}

Step-by-step explanation:

here is your answer

Calculation steps:

11  \frac{6}{9}   - 4 \frac{4}{9}

= (14 - 4)  + ( \frac{6}{9}  -  \frac{4}{9} )

= 7 +  \frac{6 - 4}{9}

=  7 +  \frac{2}{9}

7  \frac{2}{9}

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What is the inverse of f(x)=(x+6)2 for x≥–6 where function g is the inverse of function f? g(x)=x√−6, x≥0 g(x)=x−6−−−−√, x≥6 g(x
avanturin [10]

Answer:

g(x)=\sqrt{x}-6, x>=0

Step-by-step explanation:

f(x)=(x+6)^2

To find the inverse function , replace f(x) by y

y=(x+6)^2

Replace x with y and y with x

x=(y+6)^2

Solve the equation for y

take square root on both sides

+\sqrt{x} =y+6

Now subtract 6 from both sides

+\sqrt{x}-6=y

replace y with g(x)

g(x)=\sqrt{x}-6

8 0
3 years ago
Es of two children are 11 and 8 years.
nikdorinn [45]

Answer:

<em>In 5 years the product of their ages will be 208</em>

Step-by-step explanation:

The age of two children is 11 and 8 years.

Let's call x the number of years ahead.

We need to find when the product of their future ages is 208. The 11 years old child will be 11+x years old and the other child will be 8+x years, thus:

(11+x)(8+x)=208

Operating:

88+11x+8x+x^2=208

Simplifying:

x^2+19x-120=0

Factoring:

(x-5)(x+24)=0

Solving:

x=5, x=-24

The negative solution is not valid, thus x=5

In 5 years the product of their ages will be 208

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3 years ago
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3 years ago
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Con las cuatro cartas que se muestran en la figura se pueden formar diferentes números. Por ejemplo: 8232 o 3822. ¿Cuántos númer
densk [106]

Answer:

Se pueden formar 9 números pares.

Step-by-step explanation:

Dado que con cuatro cartas se pueden formar diferentes números, como por ejemplo 8232 o 3822, para determinar cuántos números pares de cuatro dígitos y diferentes puedes formar con estas cuatro cartas se debe realizar la siguiente tabla:

8232 - 8322 - 8223 = 2 pares 1 impar

2832 - 2823 - 2382 - 2328 - 2283 - 2238 = 4 pares 2 impares

3822 - 3282 - 3228 = 3 pares

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5 0
3 years ago
Need help!! I can't figure this out
Sidana [21]

9514 1404 393

Answer:

  12. $1,035,057.23

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  14. $7,762.93

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Step-by-step explanation:

The annuity and amortization formulas are used for problems like this.

  sum of monthly payments = P((1 +r/12)^(12t) -1)/(r/12)

  monthly amount available = P(r/12)/(1 -(1 +r/12)^(-12t))

__

12. The sum of monthly payments of 74, accumulated at 9% compounded monthly for 52 years is ...

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__

13. The total of payments is ...

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So, the interest earned is ...

  $1,035,057.23 -46,176 = $988,881.23

__

14. The amount available in perpetuity is the monthly interest on this account balance.

  $1,035,057.23 × .09/12 = $7,762.93

__

15. The monthly amount available for 25 years is found from the amortization formula:

  A = $1,035,057.23(.09/12)/(1 -(1 +.09/12)^(-12·25)) = $8686.16

__

16. The amortization formula is used for this, too.

  8066 = P(.094/12)/(1 -(1 +.094/12)^(-12·30)) = 0.00833568P

  P = $8066/0.00833568 = $967,647.66

7 0
3 years ago
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