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Tems11 [23]
2 years ago
12

Value of sin 30degree

Mathematics
2 answers:
Kitty [74]2 years ago
7 0

1/2

                               

. .  ..  . . . . . . . . r.f re.f .er. e. . .e .e .r ..e .er.re

GREYUIT [131]2 years ago
4 0

Answer:

0.5 is your answer. Learning about this stuff too.

Step-by-step explanation:

Or 1/2 as a fraction.

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Combine the like terms to create an equivalent expression. 8 r + 7 − 6 r − 5 8r+7−6r−5
snow_lady [41]

Answer:

62r+9

Step-by-step explanation:

Let's simplify step-by-step.

8r+7−6r−58r+7−6r−5

=8r+7+−6r+−58r+7+−6r+−5

Combine Like Terms:

=8r+7+−6r+−58r+7+−6r+−5

=(8r+−6r+−58r+−6r)+(7+7+−5)

=−62r+9

Answer:

=−62r+9

HOPE THIS HELPS!!!!!! :)

<3333333333

3 0
3 years ago
Find 18 percent of 30000​
Solnce55 [7]
The answer to 18 percent of 30000 is 5400
3 0
3 years ago
If 0 ≤ Ø &lt; 90 degrees, and tan Ø= 2/3, what is sinØ + cosØ?
Alika [10]

Answer:

1.38

Step-by-step explanation:

tan Ø = 2/3

Ø = tan⁻¹(2/3)

Ø = 33.69

sin 33.69 ≈ 0.55

cos 33.69 ≈ 0.83

sin Ø + cos Ø ≈ 1.38

4 0
3 years ago
Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 4.6 parts
kirill115 [55]

Answer:

z=\frac{4.5-4.6}{\frac{1.1}{\sqrt{860}}}=-2.666    

p_v =2*P(Z  

If we compare the p value and the significance level given \alpha=0.02 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 4.6 at 2% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=4.5 represent the sample mean

\sigma=1.1 represent the population standard deviation

n=860 sample size  

\mu_o =4.6 represent the value that we want to test

\alpha=0.02 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal or not to 4.6, the system of hypothesis would be:  

Null hypothesis:\mu = 4.6  

Alternative hypothesis:\mu \neq 4.6  

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{4.5-4.6}{\frac{1.1}{\sqrt{860}}}=-2.666  

P-value

Since is a two sided test the p value would be:  

p_v =2*P(Z  

Conclusion  

If we compare the p value and the significance level given \alpha=0.02 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 4.6 at 2% of signficance.  

5 0
3 years ago
Eva is 29 years old and has 2 children, ages 3 and 5. She makes 48,500 a year. Eva decides to buy a 400,000 10-year term policy
earnstyle [38]

Answer:

Eva would have been better off selecting the 20-year term policy.

Step-by-step explanation:

Base on the scenario been described in the question, Eva would have been better off selecting the 20-year term policy. This reason is because assuming Eva bought the 20-year term policy, she wont be paying the new charge of extra 40% to her premium rate, compared to when she bought the 10-year term policy then renew the policy for another ten years.

3 0
3 years ago
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