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2 years ago

What is the sum of the first 20 terms of the series below?

Mathematics

2 answers:

Evgesh-ka [11]2 years ago

7 0

the sum of the first 20 terms of the series below is C.

Natalija [7]2 years ago

6 0

Answer:

Step-by-step explanation:

Now to find the sum of first 20 terms, substitute n=20,a=−1 and d=4 in S n = 2n [2a+ (n−1)d] as follows: S 20 = 220 [(2×−1)+(20−1)4]=10[−2+(19×4)]=10(−2+76)=10×74=740 Hence, the sum of first 20 terms is 740.

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

MAXImum [283]

Answer:

x = 15/p
x = -3

Step-by-step explanation:

Given expression

4(px+1)=64

Solving for x

4px + 4 = 64
4px = 60
px = 15
x = 15/p

Value of x when p= - 5

x = 15/(-5) = -3

3 0

3 years ago

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10^(-10log3) How to solve this???

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3 years ago

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ivolga24 [154]

Answer:

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Step-by-step explanation:

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3 years ago

Find 2 numbers, if their sum is -11 and their difference is 41

frosja888 [35]

Answer:

15, -26

Step-by-step explanation:

The generic solution to a "sum and difference" problem can be found easily. Let "a" and "b" represent the numbers you seek, and let "s" and "d" represent their sum and difference:

a + b = s

a - b = d

Adding these two equations tells you ...

2a = s + d

a = (s + d)/2 . . . . . . divide by the coefficient of a

You can find "b" several different ways. One way is to subtract the second equation from the first:

2b = s - d

b = (s - d)/2 . . . . . . divide by the coefficient of b

So, the second number can be found from any of ...

b = s - a
b = a - d
b = (s - d)/2

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For the numbers given here, s=-11, d=41, the two numbers are ...

a = (-11 +41)/2 = 15

b = -11 -15 = -26

The two numbers are 15 and -26.

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3 years ago

HELP PLEASEE 11. a) find two integers with a sum of -1 and a difference of +5.

e-lub [12.9K]

Answer:

-3 and 2

Step-by-step explanation:

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3 years ago