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dusya [7]
3 years ago
11

The standard distance that has to be travelled by a rocket in 1 second is 7.9 km. A new rocket is built for a space expedition b

ut the distance that can be travelled by the new rocket in an hour is only 3.75 10 km.
(i) What is the standard distance, in km, that has to be travelled by a rocket in an hour?

(ii) What is the difference between the distance that can be travelled by the new rocket and the standard distance required in an hour?​
Mathematics
1 answer:
jeka57 [31]3 years ago
7 0

Step-by-step explanation:

What is the difference between the distance that can be travelled by the new rocket and the standard distance required in an hour?

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Two wheels rolled simultaneously. The radius of the smaller wheel is r feet and the radius of the larger wheel is 2r feet If bot
Mnenie [13.5K]
The smaller wheel rolled
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The larger wheel rolled
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The larger wheel traveled (16πr -8πr) = 8πr feet farther than the small wheel.
6 0
4 years ago
What is the solution of the equation √2x-3-3=6?<br><br><br> A) 42 <br> B) 39<br> C) 3<br> D) 6
Firlakuza [10]

Answer:

42

Step-by-step explanation:

√2x-3-3=6

√2x-3=6+3

√2x-3=9

2x-3=9^2

2x=81+3

X=84/2

X=42

So value of X is 42

4 0
3 years ago
I will give brainliest fast please I will give points please explain well
ANEK [815]

If the equal is 55x + 35y = 200

x: time-driven at 55 miles/hour

y: time-driven at 35 miles/hour

If the car spends 2.5 hours at 35 miles per hour, then it drove:

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    55x =35

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4 0
2 years ago
Factor y2 + 10z - 10y - yz
stira [4]
Group and factor
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(y²-10y)+(10z-yz)
factor
y(y-10)+z(10-y)
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6 0
3 years ago
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Kay [80]
We know that
the equation of the vertical parabola in the vertex form is
<span>y=a(x-h)²+k
</span>where 
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if a> 0 then
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if a< 0
then the parabola open downwards

in this problem  we have
f(x)=−5(x+7)²<span>+6
</span>a=-5
so
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the vertex is the point (-7,6) is a maximum

the answer is the option
<span>a = -5, opens down</span> 

see the attached figure

6 0
3 years ago
Read 2 more answers
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