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ser-zykov [4K]
2 years ago
7

Which is the value of this expression when p = -2 and q = -1?

Mathematics
1 answer:
Pie2 years ago
7 0

Answer:

Here is the ans...hope it helps:)

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Determine the solution to 11y = 37.4.
Annette [7]
Y= 3.4. If you divide 37.4 by 11 then y would equal 3.4. Check by multiplying 3.4 by 11
8 0
4 years ago
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16. A company spends $100 per day on fixed expenses such as electricity, rent, and the like. It also spends $35 per day on each
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C = Total Daily Cost
Total Daily Cost = (Salary per employee per day)×(Total no. of employees on that day) + Fixed Expenses.

C = 35x + 100
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3 years ago
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In the game of​ roulette, a player can place a ​$9 bet on the number 11, and have a 1/38 probability of winning. If the metal ba
damaskus [11]

Answer:

1. What is the expected value of the game to the​ player?

Expected value= -$0.47368

2. If you played the game 1000​ times, how much would you expect to​ lose?

Expected value= -$473.68

Step-by-step explanation:

1. What is the expected value of the game to the​ player?

Expected value can tell how much you will gain/lose every time you do the game. To find the expected value you need to multiply every value with its chance to occur. There are two types of events here, winning and losing. You have 1/38 chance of winning $315 and 37/38 chance of losing $9.  

The expected value will be:

expected value= 1/38 * $315 + 37/38*(-$9) = $8.2894 - $8.7631

expected value= -$0.47368

You are expected to lose $0.47368 every time you play

2. If you played the game 1000​ times, how much would you expect to​ lose?

Expected value calculated for each roll. If you want to know how much you gain/lose by multiple rolls, you just need to multiply the expected value with the number of rolls. The game has negative expected value so you are expected to lose money instead of gaining money. The money you expected to lose will be:

number of roll * expected value

1000 timer * -$0.47368/time= -$473.68

You are expected to lose $473.68 if you play the game 1000 times.

6 0
3 years ago
In kindergarten there are 103 children 49 of them wore silly costumes and 36 of them wore character costumes. Did any if the chi
elixir [45]

Answer:

Yes, `18 of them wore a different costume

Step-by-step explanation:

49+36=85 which is not 103 children

So then you take 103 and subtract 85 (103-85= 18)

And your answer is 18, so 18 of the children wore a different type of costume.

5 0
3 years ago
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for large parties, a restaurant adds a 15% service charge to the bill. How much would be added to a bill of 638.40
sp2606 [1]

It would be 734.16 because 638.40+15% = 734.16

6 0
3 years ago
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