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2 years ago

Compare and contrast the following two equations. Determine if they are linear equations and explain why or why not.

Mathematics

1 answer:

igor_vitrenko [27]2 years ago

7 0

Answer:

xy = -1 and y = -1/x are the same.

They are not linear equations because they are not written in the form

Ax + By = C.

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What makes (a + 2)(b – 9) = 0 true?

prohojiy [21]

B would have to equal 9 and a should equal -2 to get 0

5 0

3 years ago

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I need help rlly bad I have no idea what’s the answer plsss help me!!!

lyudmila [28]

Answer:

n = 6 $\sqrt{3}$

Step-by-step explanation:

Using the sine ratio in the right triangle and the exact value

sin30° = $\frac{\sqrt{3} }{2}$ , then

sin30° = $\frac{opposite}{hypotenuse}$ = $\frac{n}{12}$ = $\frac{\sqrt{3} }{2}$ ( cross- multiply )

2n = 12 $\sqrt{3}$ ( divide both sides by 2 )

n = 6 $\sqrt{3}$

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2 years ago

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Using Newton's Method, what is the formula for determining the nth term in a sequence of approximations to a solution of a polyn

lorasvet [3.4K]

Step-by-step explanation:

in newton rapson method

$x_{n+1}=x_{n}-\frac{f\left(x_{n}\right)}{f^{\prime}\left(x_{n}\right)}$

Let $n=n-1$

$x_{(n-1)+1}=x_{n-1}-\frac{f\left(x_{n-1}\right)}{f^{\prime}\left(x_{n-1}\right)}$

$x_{n}=x_{n-1}-\frac{f\left(x_{n-1}\right)}{f^{\prime}\left(x_{n-1}\right)}$

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2 years ago

Which reason justifies the last step in a proof that ∆DEF ≅ ∆DAB?

lesya [120]

Hey there, Sheriawilright!

The correct answer should be C since we are given two sides AD is congruent to ED and D is the midpoint of Line BF meaning that BD and BF are the same. Also, it makes both lines make a vertical angle meaning they are the same. So we have two sides and an angle between, so the answer is Side Angle Side.

Thank you for using Brainly.
See you soon!

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3 years ago

The functions f and g are defined by f: x = 4 - x and g: x = hx² + k. If the composite function gf is given by gf: x + 2x² - 16x

kozerog [31]

Answer:

Step-by-step explanation:

f(x) = 4-x

g(x) = h $x^{2}$ +k

g(f(x)) = 2 $x^{2}$ -16x+26

so put f(x) in g(x)

h $(4-x)^{2}$ +k

h((4-x)(4-x) + k

h( $x^{2}$ -8x+16)+k

if h = 2 , then

2 $x^{2}$ -16x+32 + k

and we want 26 instead of 32 so subtract 6 so K = (-6)

2 $x^{2}$ -16x+32 + (-6)

2 $x^{2}$ -16x+32 - 6

2 $x^{2}$ -16x+26

h=2

k=(-6)

5 0

2 years ago