1 machine 5 min. 1 object
100 machine x min. 100 object
so than from this result that for 100 machine to make 100 objects need 5 minutes
hope this will help you
1) Road Trip: Let’s say two friends are meeting at a playground. Mary is already at the park but her friend Bob needs to get there taking the shortest path possible. Bob has two way he can go - he can follow the roads getting to the park - first heading south 3 miles, then heading west four miles. The total distance covered following the roads will be 7 miles. The other way he can get there is by cutting through some open fields and walk directly to the park. If we apply Pythagoras's theorem to calculate the distance you will get:
(3)<span>2 </span>+ (4)2 =
9 + 16 = C2
√25 = C
5 Miles. = C
Walking through the field will be 2 miles shorter than walking along the roads. .
2) Painting on a Wall: Painters use ladders to paint on high buildings and often use the help of Pythagoras' theorem to complete their work. The painter needs to determine how tall a ladder needs to be in order to safely place the base away from the wall so it won't tip over. In this case the ladder itself will be the hypotenuse. Take for example a painter who has to paint a wall which is about 3 m high. The painter has to put the base of the ladder 2 m away from the wall to ensure it won't tip. What will be the length of the ladder required by the painter to complete his work? You can calculate it using Pythagoras' theorem:
(5)<span>2 </span>+ (2)2 =
25 + 4 = C2
√100 = C
5.3 m. = C
Thus, the painter will need a ladder about 5 meters high.
3) Buying a Suitcase: Mr. Harry wants to purchase a suitcase. The shopkeeper tells Mr. Harry that he has a 30 inch of suitcase available at present and the height of the suitcase is 18 inches. Calculate the actual length of the suitcase for Mr. Harry using Pythagoras' theorem. It is calculated this way:
(18)<span>2 </span>+ (b)2 = (30)2
324 + b2 = 900
B2 = 900 – 324
b= √576
= 24 inches
Answer:
false i think? and true
Step-by-step explanation:
Answer:
3x times 3x times 3x times 3x + x^3 + 3x times 2x times 3x times 2x + 2x
or
x^3 + 2x^3 + 3x^6
Step-by-step explanation:
3x^4 + x^3 + 6x^2 + 2x
3x times 3x times 3x times 3x + x^3 + 6x times 6x + 2x
3x times 3x times 3x times 3x + x^3 + 3x times 2x times 3x times 2x + 2x
x^3 + 2x^3 + 3x^6
Answer:
Step-by-step explanation:
First and foremost, all quadratics have a domain of all real numbers (as long as we are not given only a portion of the graph, or one with endpoints. Our graph does not have endpoints, so it is assumed that the tails will continue to go down into negative infinity and at the same time, the x coordinates will keep growing as well.) Since our quadratic is upside down, it has a max. That means that none of the values on the graph will be above that point. All the values will be below that highest point (the highest y-value). Y-values indicate range, and since our highest y-value is at y = 2, then the range is
y ≤ 2
