Answer:
cos theta = adja/ hypo
adja=8
hypo=17
cos theta= 8/17=0.47
theta= cos^-1 0.47
theta=1.0815
to fine missing side, use Pythagoras
hypo²= oppo² + adja²
17²= oppo² + 8²
289-64=oppo²
oppo²=225
oppo=15
We know that
case a)the equation of the vertical parabola write in vertex form is
y=a(x-h)²+k,
where (h, k) is the vertex.
Using our vertex, we have:
y=a(x-2)²-1
We know that the parabola goes through (5, 0),
so
we can use these coordinates to find the value of a:
0=a(5-2)²-1
0=a(3)²-1
0=9a-1
Add 1 to both sides:
0+1=9a-1+1
1=9a
Divide both sides by 9:
1/9 = 9a/9
1/9 = a
y=(1/9)(x-2)²-1
the answer isa=1/9case b)the equation of the horizontal parabola write in vertex form is
x=a(y-k)²+h,
where (h, k) is the vertex.
Using our vertex, we have:
x=a(y+1)²+2,
We know that the parabola goes through (5, 0),
so
we can use these coordinates to find the value of a:
5=a(0+1)²+2
5=a+2
a=5-2
a=3
x=3(y+1)²+2
the answer isa=3
see the attached figure
Answer:
this is this because of PTI
Step-by-step explanation:
pto explain it to me on Monday and Friday Saturday morning
Answer:
sorry I'm editing this to apologize, because I put the wrong answer on here. I said it was D, but this is NOT correct. I do not know the answer so I am sorry, but I cant delete my answer know that I've already posted it.... forgive me
Step-by-step explanation:
The answer to that problem is 4. 4*4*4*4=(4*4)*(4*4)=16*16=256. I hope this helped!