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2 years ago

Hello I need help on this math question ignore the circled answer just give me the correct answer thankyou :)

Mathematics

1 answer:

Anna71 [15]2 years ago

3 0

Answer:

Option C is correct...hope this helps:)

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(2a)(2b) please help

DENIUS [597]

The answer is 2^a+b lol

3 0

3 years ago

Jane is 5 times older than her sister. In 3 years, Jane’s sister will be 1/4 her age. Find the ages now

Korolek [52]

The present age of Jane is 45 years old and present age of her sister is 9 years old

<em><u>Solution:</u></em>

Let the present age of Jane be "x"

Let the present age of her sister be "y"

<em><u>Jane is 5 times older than her sister</u></em>

present age of Jane = 5(present age of her sister)

x = 5y ---------- eqn 1

<em><u>In 3 years, Jane’s sister will be 1/4 her age</u></em>

Age of sister after 3 years = 3 + y

Age of jane after 3 years = 3 + x

Age of sister after 3 years = 1/4(age of jane after 3 years)

$3 + y = \frac{1}{4}(3 + x)$

Substitute eqn 1 in above equation

$3 + y = \frac{1}{4}(3 + 5y)\\\\12 + 4y = 3 + 5y\\\\5y - 4y = 12 - 3\\\\y = 9$

Substitute y = 9 in eqn 1

x = 5(9)

x = 45

Thus present age of Jane is 45 years old and present age of her sister is 9 years old

3 0

4 years ago

I really need some help with this. Please no guesses, I need an exact answer. Thank you in advance.

alexandr1967 [171]

40 degrees
$80 + 60 = 140 \\ 180 - 140 = 40$

3 0

3 years ago

Perimeter, Area And Volume

Maslowich

$\large\huge\green{\sf{Answer:-}}$

<h3>area of shaded figure= </h3>

<h2>area of whole rectangle</h2>

= lengthx breadth=15x30= 450 cm²

<h3>area of unshaded region= lengthx breadth= (30-8)x 15cm²= 22x 15cm²= 330cm²</h3>

<h3>are of shaded region</h3>

= area of whole rectangle -area of unshaded region= 450cm²-330cm²= 120cm²

therefore 120 is correct answer

6 0

3 years ago

Look at this cylinder:

Sedbober [7]

Height=h=8cm
Radius=r=4cm

We know

$\boxed{\sf \star TSA_{(Cylinder)}=2\pi r(h+r)}$

$\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=2\times \dfrac{22}{7}\times 4(8+4)$

$\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=\dfrac{176}{7}(12)$

$\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=\dfrac{2112}{7}$

$\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=301.7cm^2$

Now

New Radius=2(4)=8cm
New Height=2(8)=16cm

$\\ \sf\longmapsto TSA_{(New\:Cylinder)}=2\times \dfrac{22}{7}\times 8(16+8)$

$\\ \sf\longmapsto TSA_{(New\:Cylinder)}=\dfrac{352}{7}(24)$

$\\ \sf\longmapsto TSA_{(New\:Cylinder)}=\dfrac{8448}{7}$

$\\ \sf\longmapsto TSA_{(New\:Cylinder)}=1204.7cm^2$

$\\ \sf\longmapsto \dfrac{TSA_{(New\:Cylinder)}}{TSA_{(Old\:Cylinder)}}=\dfrac{1204.7}{301.7}$

$\\ \sf\longmapsto \dfrac{TSA_{(New\:Cylinder)}}{TSA_{(Old\:Cylinder)}}=\dfrac{4}{1}$

$\\ \sf\longmapsto\underline{\boxed{\bf{ {TSA_{(New\:Cylinder)}}:{TSA_{(Old\:Cylinder)}}=4:1}}}$

Hence our correct option is Option C

6 0

3 years ago