I think you have to first separate the integral:1/(1+v^2) + v/(1+v^2),
so the integral of the first term is ArcTan (v) and for the integral of the second term i recommend you to do a change of variable:
y= 1+v^2
so
dy= 2v
and
v= dy/2and then you substitute:v/(1+v^2) = (1/2)(dy/y)
and the integral is
(1/2) (In y)finally you plug in the initial variables:
(1/2)(In [1+v^2])
so the total integral is:
ArcTan (y) + (1/2)(In [1+v^2])
1) this is simply solving it, so if you divide 16 by 3, you end up getting 5 1/3
2) 3 1/2, by multiplying 7 by 1/2
3) 224, by multiplying 14 by 16
4) 54 mph, by dividing 324 by 6
5) blue, because only the 1/4 ribbon color would be collected after 3/4 mile
6) 7/8 - 3/8 equals 4/8, or 1/2 when simplified
Step-by-step explanation:
(n-m) out of n
not sure if this is correct or something....
Answer:
The system of inequalities is
y\geq 3x-2
y<-(1/5)x+2
Step-by-step explanation:
step 1
Find the equation of the solid blue line
Let
A(0,-2), B(1,1)
Find the slope of AB
m=(1+2)/(1-0)=3
The equation of the line into slope intercept form is equal to
y=mx+b
we have
m=3
b=-2 - ----> the point A is the y-intercept
substitute
y=3x-2 - -----> equation of the solid blue line
The solution of the inequality is the shaded area above the solid line
therefore
The first inequality is
y\geq 3x-2
C(0,2), D(5,1)
step 2
Find the equation of the dashed red line
Let
Find the slope of CD
m=(1-2)/(5-0)=-1/5
The equation of the line into slope intercept form is equal to
y=mx+b
we have
m=-1/5
b=2 ----> the point C is the y-intercept
substitute
y=-(1/5)x+2 -----> equation of the dashed red line
The solution of the inequality is the shaded area below the dashed line
therefore
The second inequality is
y<-(1/5)x+2
The system of inequalities is
y\geq 3x-2
y<-(1/5)x+2
