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leva [86]
2 years ago
6

J3.

Mathematics
1 answer:
alisha [4.7K]2 years ago
3 0

By using the given table, we can see that the expected value is 20.97 AED.

<h3>How to find the expected value?</h3>

The expected value is given by the sum between the products between the value of each outcome and the probability of said outcome.

Then, by using the table, we can write the expected value as:

12*0.8 + 18*0.15 + 20*0.31 + 22*0.08 + 24*0.15 + 25*0.23 = 20.97

Then we can see that the correct option is C, the expected value is 20.97 AED.

If you want to learn more about expected value:

brainly.com/question/15858152

#SPJ1

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Find the zeroes of the polynomial function f(x)=x^4-5x^3+11x^2-25x+30.
katen-ka-za [31]

Step-by-step explanation:

x⁴ − 5x³ + 11x² − 25x + 30

x⁴ − 5x³ + 6x² + 5x² − 25x + 30

x² (x² − 5x + 6) + 5 (x² − 5x + 6)

(x² + 5) (x² − 5x + 6)

(x² + 5) (x − 2) (x −3)

The zeros are 2, 3, and ±√5i.

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3 years ago
A car radiator needs a 80% antifreeze solution. The radiator now holds 15 liters of a 70% solutions. How many liters of this sho
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So... the radiator has 15 liters of 70% antifreeze.. but needs an 80% antifreeze

well, so, you need to drain some and put some with higher percentage, seems to be, you will end up at the same 15 liters, possible the radiator's capacity, of 80% antifreeze

so, the same amount going out, of 70% is the same amount going in, of 100% antifreeze

now.. let's use the decimal format for the percents, or 70% is 70/100 or 0.7 and so on
\bf \begin{array}{lccclll}&#10;&amount&concentration&&#10;\begin{array}{llll}&#10;concentration\\&#10;amount&#10;\end{array}\\&#10;&-----&-------&-------\\&#10;\textit{70\% sol'n, out}&x&0.7&0.7x\\&#10;\textit{100\% sol'n, in}&x&1.00&x\\&#10;\textit{current 70\% sol'n}&15&0.7&10.5\\&#10;-----&-----&-------&-------\\&#10;mixture&15&0.8&12&#10;\end{array}

so.. let's subtract, from the current solution, 0.7x and add 1x or x, our antifreeze concentration amount, should be 12 though

10.5 - 0.7x + x = 12

solve for "x"

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Part of the arena is being turned into a public darkroom. The floor needs covering in rubber tiles before work can begin on the
vladimir2022 [97]

The number of tiles used is 300 tiles.

According to the statement

We have given that:

The tiles are 20 cm by 30 cm. And the dark room floor is 6 meters by 3 meters.

And we have to find that the number of tiles used to prepare the dark room.

So, For this purpose we have to find the area of the room floor.

The area of the floor is 6 *3.

The area of the floor is 18 meter per square.

The area of the tile is 0.2*0.3

The area of the tile is 0.06 meter per square.

Now,

The number of tiles used is 18/0.06

The number of tiles used is 300.

So, The number of tiles used is 300 tiles.

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Answer:

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This is horizontal line, so the slope is undefined.

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