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FrozenT [24]
2 years ago
15

Which of the following is true regarding the solution to the logarithmic equation below? log subscript 2 baseline (x 11) = 4. x

11 = 2 superscript 4. x 11 = 16. x = 5.
Mathematics
2 answers:
Darina [25.2K]2 years ago
7 0

Answer:

C, x = 5 is a true solution because log Subscript 2 Baseline (16) = 4

Step-by-step explanation:

edge

frez [133]2 years ago
4 0

The value of x is 5. Thus, the correct statement is:

x = 5 is a true solution because log subscript 2 Baseline (16) = 4

<h3>Data obtained from the question </h3>
  • Log₂ (x + 11) = 4
  • Value of x =?
<h3>How to determine the value of x </h3>

Log₂ (x + 11) = 4

x + 11 = 2⁴

x + 11 = 16

Collect like terms

x = 16 – 11

x = 5

<h3>**Check** </h3>

Log₂ (x + 11) = 4

x = 5

Log₂ (5 + 11) = 4

Log₂ 16 = 4

Find the value of Log₂ 16

Log₂ 16 = n

16 = 2ⁿ

2⁴ = 2ⁿ

n = 4

Thus,

Log₂ 16 = 4

Therefore, the correct answer to the question is:

x = 5 is a true solution because log subscript 2 Baseline (16) = 4

Complete question

Which of the following is true regarding the solution to the logarithmic equation below? log Subscript 2 Baseline (x + 11) = 4. x + 11 = 2 Superscript 4. x + 11 = 16. x = 5. x = 5 is not a true solution because log Subscript 5 Baseline (16) not-equals 2 x = 5 is not a true solution because log Subscript 5 Baseline (16) not-equals 4 x = 5 is a true solution because log Subscript 2 Baseline (16) = 4 x = 5 is a true solution because log Subscript 4 Baseline (16) = 2

Learn more about Logarithm equation:

brainly.com/question/7302008

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8 0
3 years ago
If f(x)=x+7 and g(x)= 1 divided by x-13, what is the domain of (f•g)(x)?
andrew11 [14]
<h2>Hello!</h2>

The answer is:

The domain of the function is all the real numbers except the number 13:

Domain: (-∞,13)∪(13,∞)

<h2>Why?</h2>

This is a composite function problem. To solve it, we need to remember how to composite a function. Composing a function consists of evaluating a function into another function.

Composite function is equal to:

f(g(x))=(f\circ} g)(x)

So, the given functions are:

f(x)=x+7\\\\g(x)=\frac{1}{x-13}

Then, composing the functions, we have:

f(g(x))=\frac{1}{x-13}+7\\

Therefore, we must remember that the domain are all those possible inputs where the function can exists, most of the functions can exists along the real numbers with no rectrictions, however, for this case, there is a restriction that must be applied to the resultant composite function.

If we evaluate "x" equal to 13, the denominator will tend to 0, and create an indetermination since there is no result in the real numbers for a real number divided by 0.

So, the domain of the function is all the real numbers except the number 13:

Domain: (-∞,13)∪(13,∞)

Have a nice day!

5 0
3 years ago
Helpppppppppppppppppppp
Effectus [21]
Simple proportions.

You want a 1:5 ratio.
You have a 5:1 ratio.
So you add another 24 drops of white.
5:25 = 1:5 
or
5/x = 1/5 and cross multiply.
7 0
3 years ago
Jon collects 2,578 ounces of honey from his beehive. he will put the honey in jars that hold 6 ounces each. which expression is
belka [17]

Answer:

With j = number of jars: 2,578 / 6 = j

Step-by-step explanation:

8 0
3 years ago
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