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Anuta_ua [19.1K]
3 years ago
12

on the road in a certain city, the maximum speed is 60nmiles per hour and the minimum speed is 20 miles per hour. if x represent

s speed, which sentence best expresses this condition?
Mathematics
1 answer:
USPshnik [31]3 years ago
4 0
20 greater than or equal to X less than or equal to 60
20 _
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Which of the following tables does not represent a linear relationship between x and y?
vovangra [49]

Answer:

The first one is not liner

Step-by-step explanation:

This isn't linear because the y values increase inequally. It adds 2 and then 3 instead of keeping a constant rate

6 0
3 years ago
A regular six sided die and an eight equal segment spinner, numbered 1 to 8, are rolled/spun simultaneously. What are the odds i
kirill [66]

Answer:

1/3

Step-by-step explanation:

In statistics, the probability of both an event A and an event B happening is equal to the probability of A happening multiplied by the probability of event B happening.

Let's say spinning a prime number is event A and rolling a number ≤ 4 is event B.

There are 8 possibilities on an eight equal segment spinner, and there are 4 prime numbers between 1 and 8 (including 8), which are 2, 3, 5, and 7. This means that the probability of spinning a prime number is 4/8, or 1/2

There are 6 possibilities on a die, and there are 4 possibilities of rolling a 4 or less (1, 2, 3, 4). Therefore, the probability of rolling 4 or less on a die is 4/6, or 2/3

The probability of both of these happening can be calculated by multiplying these together, so 1/2 * 2/3 = 2/6 = 1/3

8 0
2 years ago
Q
katrin2010 [14]

Answer:

v= -(-v)

Step-by-step explanation:

3 0
3 years ago
If f(x)=|2x-4| find f(-7)
Yuri [45]

Answer:

18

Step-by-step explanation:

sub in x = -7 into the equation

f(-7) = |-14-4| = |-18| = 18

4 0
1 year ago
Show work please.<br><br> solve system of equations using matrices.
nadya68 [22]

Answer:

(t, t -1, t)

Step-by-step explanation:

You have three unknowns but only 2 equations, so you can't really SOLVE this...you can get a solution with a variable still in it (I forget what this is called.  I think it refers to infinite many solutions).  Here's how it works:

Set up your matrix:

\left[\begin{array}{ccc}1&-2&1\\2&-1&-1\\\end{array}\right] \left[\begin{array}{ccc}2\\1\\\end{array}\right]

You want to change the number in position 21 (the 2 in the scond row) to a 0 so you have y and z left.  Do this by multiplying the top row by -2 then adding it to the second row to get that 2 to become a 0.  Multiplying in a -2 to the top row gives you:

\left[\begin{array}{ccc}-2&4&-2\\2&-1&-1\\\end{array}\right]\left[\begin{array}{ccc}-4\\1\\\end{array}\right]

Then add, keeping the first row the same and changing the second to reflect the addition:

\left[\begin{array}{ccc}-2&4&-2\\0&3&-3\\\end{array}\right] \left[\begin{array}{ccc}-4\\-3\\\end{array}\right]

The second equation is this now:

3y - 3z = -3.  Solving for y gives you y = z - 1.  Let's let z = t (some random real number that will make the system true.  Any number will work.  I'll show you at the end.  Just bear with me...)

lf z = t, and if y = z - 1, then y = t - 1.  So far we have that y = t - 1 and z = t.  Now we solve for x:

From the first equation in the original system,

x - 2y + z = 2.  Subbing in t - 1 for y and t for z:

x - 2(t - 1) + t = 2.  Simplify to get

x - 2t + 2 + t = 2  and  x - t = 0, and x = t.  So the solution set is (t, t - 1, t).  Picking a random value for t of, let's say 2, sub that in and make sure it works.  If:

x - 2y + z = 2, then t - 2(t - 1) + t = 2 becomes t - 2t + 2 + t = 2, and with t = 2, 2 - 2(2) + 2 + 2 = 2.    Check it:  2 - 4 + 4 = 2 and 2 = 2.  You could pick any value for t and it will work.

6 0
3 years ago
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