The value of limit of startfraction startroot x + 2 endroot minus 3 over x minus 7 endfraction when x approaches 7 is 1/6.
<h3>How to evaluate a function for a given value?</h3>
To evaluate a function for a particular value, plug in the value of the variable in the function.
The expression given in the problem is,
Multiply the factor √(x+2)+3 above and below of fraction,
The value of x tents to 7. Thus,
1/(3+3)=1/6
Thus, the value of limit of startfraction startroot x + 2 endroot minus 3 over x minus 7 endfraction when x approaches 7 is 1/6.
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