Question

Find the missing side lengths. Leave your answers as radicals in simplest form.

Answer 1

The length of missing sides x = 5 units and y = 5 units.

What is Trigonometric ratios?

The six trigonometric ratios are sine (sin), cosine (cos), tangent (tan), cotangent (cot), cosecant (cosec), and secant (sec).

In ΔABC,

AB (Base) = y  ,      BC(Hypotenuse) = $5\sqrt{2}$   ,       CA (perpendicular) = x

and ∠ABC = $45^0$

Now,

tan $45^0$  = perp. / base

1 = x /y

x= y .................(i)

again,

sin $45^0$ = perp. / Hypo.

$\frac{1}{\sqrt{2} } = \frac{x}{5\sqrt{2} }$

x = 5

put in equation (i), we get

y = 5

Thus, the length of missing side of the given triangle is x = 5 units and y =  5 units.

Learn more about trigonometric ratios from :

brainly.com/question/1201366

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