Answer:
Let the marked price be x
Discount % = 10%
Discount = 10\% \times x = 0.1x10%×x=0.1x
Cost after discount = x-0.1x = 0.9x
10%vat is charged on it
Cost including VAT = 0.9x+0.1(0.9x)=0.99x0.9x+0.1(0.9x)=0.99x
We are given that it's price became rs 1672
So, 0.99x = 1672
x=\frac{1672}{0.99}x=0.991672
x=1688.88
Discount = 0.1x=0.1(1688.88)=168.888
Hence The discount
Answer:
see explanation
Step-by-step explanation:
Parallel lines have equal slopes.
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
L₁ is y = 5x + 1 ← in slope- intercept form
with slope m = 5
L₂ is 2y - 10x + 3 = 0 ( subtract - 10x + 3 from both sides )
2y = 10x - 3 ( divide all terms by 2 )
y = 5x - 
← in slope- intercept form
with slope m = 5
Since L₁ and L₂ have equal slopes then they are parallel lines
Answer:
i)W = 2500 / T
ii) W = 500 Tons
iii) grad W(10°) = - 25î
iv) The formulation is not practical
Step-by-step explanation:
i) Write an equation describing the use of coal
As use of coal is inversely proportional to the average monthly temperature
if W is use of coal in tons/per month then
W(t) = k / T where k is a constant of proportionality and T is the average temperature in degrees. We have to determine k from given conditions
k = ?? we know that when T = 25° W = 100 tons the by subtitution
W = k/T 100 = k /25 k = 2500 Tons*degree
Then final equation is:
W = 2500 / T
ii) Find the amount of coal when T = 5 degrees
W = 2500 / 5
W = 500 Tons
iii)
The inverse proportionality implies that W will decrease as T increase.
The vector gradient of W function is:
grad W = DW(t)/dt î
grad W = - 2500/T² î
Wich agrees with the fact that W is decreasing.
And when T = 100°
grad W(10°) = - 2500/ 100 î ⇒ grad W(10°) = - 25î
iv) When T = 0 The quantity of coal tends to infinite and the previous formulation is not practical
Answer:
29
Step-by-step explanation:
Assume the number as x
2x - 9 = 49
2x = 58
x = 29
