P = how many cars Peter has
j = how many cars Jade has
a = how many cars Andre has
p x 4 = how many cars Andre has (36 model cars)
>>>TO FIND HOW MANY MODEL CARS PETER HAS:
p x 4 = 36
36 / 4 = 9
your equation to find how many model cars Peter has is:
36 / 4 = 9
So, Peter has 9 model cars.
>>>TO FIND HOW MANY MODEL CARS JADE HAS:
36 / 4 = how many cars Peter has (9)
Now, you are given the info that Jade has THREE TIMES (3x) as many cars as Peter already.
So, your equation for this one is:
9 x 3 = 27
So Jade has 27 model cars.
---- Jade has 27 model cars.
---- Andre has 36 model cars.
---- Peter has 9 model cars.
equation for a. 36 / 4 = p
equation for b. 9 x 3 = j
It is about 26.2 miles.
1 foot = about 0.000189394
The measurement of angle ABC is
B) 217 1/2
Hope this helps...
Answer:
11) Here given Function,

And, 
For f(x) = g(x)






When we solve this equation,
We found,
x = 12.5227 ≈ 12.53
Thus, the required solution is, x = 12.53
12) Here the height of rocket A in x second,

And, The height gain by the rocket B in x seconds,

If at x seconds both A and B gain the same height,
That is, f(x) = g(x)
⇒ 
⇒
⇒ 
⇒ 
⇒ x = 1.125 ≈ 1.13
Thus, the required solution is x = 1.13 seconds (approx)
Answer:
i cant see the link try reposting
Step-by-step explanation: