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2 years ago

Is square root of 81 a real number

Mathematics

2 answers:

spayn [35]2 years ago

7 0

yes, the answer is 9. ,,,,

ahrayia [7]2 years ago

4 0

Answer:

is 9

Step-by-step explanation:

9 x 9 = 81

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A machine used to fill gallon-sized paint cans is regulated so that the amount of paint dispensed has a mean of 125 ounces and a

WARRIOR [948]

Yes, so it gets the right amount in the paint can and doesn't make a mess.

7 0

3 years ago

A rectangle has a width that is 1/8 its length. If the perimeter of the rectangle is 126 inches, what is the width of the rectan

KiRa [710]

L=x
b=x/8
2(l+b)=126
2(x+x/8)=126
2(9x/2)=126
9x/2=63
9x=126
×=14 length
x/8=14/8
breadth =1.75 inches

6 0

3 years ago

A jar contains n nickels and d dimes. There are 28 coins in the jar, and the total value of the coins is $2.30. How many nickels

vova2212 [387]

Answer: You'll have 10 nickels and 18 dimes.

Step-by-step explanation:

Its a guessing question.

10 nickles = .50

18 dimes = $1.80

$1.80 + .50= 2.30

8 0

3 years ago

Which statement describes the sequence defined by a Subscript n Baseline = StartFraction n cubed minus n Over n squared + 5 n En

Dominik [7]

Answer:

The answer is " The sequence converges to infinity. "

Step-by-step explanation:

Given:

$\to a_n=\frac{n^3-n}{n^2+5n}$

$\lim_{n \to \infty} a_n= \lim_{n \to \infty} \frac{n^3-n}{n^2+5n}$

$= \lim_{n \to \infty} \frac{n(n^2-1)}{n(n+5)}\\\\= \lim_{n \to \infty} \frac{(n^2-1)}{(n+5)}\\\\= \lim_{n \to \infty} \frac{n(n-\frac{1}{n})}{n(1+\frac{5}{n})}\\\\= \lim_{n \to \infty} \frac{(n-\frac{1}{n})}{(1+\frac{5}{n})}\\\\$

Denominator $= \lim_{n \to \infty} 1+\frac{5}{n}=1+\lim_{n\to \infty} \frac{5}{n}=1+0=1$

Numerator $=\lim_{n\to \infty}n-\frac{1}{n}=\infty$

$\therefore\\\\\lim_{n\to \infty}a_n=\frac{\infty}{1} =\infty$

7 0

3 years ago

Read 2 more answers

*(The bottom part is x as it approaches infinity)*

Bess [88]

$\bf \lim\limits_{x\to \infty}~\left( \cfrac{1}{8} \right)^x\implies \lim\limits_{x\to \infty}~\cfrac{1^x}{8^x}\\\\[-0.35em] ~\dotfill\\\\ \stackrel{x = 10}{\cfrac{1^{10}}{8^{10}}}\implies \cfrac{1}{8^{10}}~~,~~ \stackrel{x = 1000}{\cfrac{1^{1000}}{8^{1000}}}\implies \cfrac{1}{8^{1000}}~~,~~ \stackrel{x = 100000000}{\cfrac{1^{100000000}}{8^{100000000}}}\implies \cfrac{1}{8^{100000000}}~~,~~ ...$

now, if we look at the values as "x" races fast towards ∞, we can as you see above, use the values of 10, 1000, 100000000 and so on, as the value above oddly enough remains at 1, it could have been smaller but it's constantly 1 in this case, the value at the bottom is ever becoming a larger and larger denominator.

let's recall that the larger the denominator, the smaller the fraction, so the expression is ever going towards a tiny and tinier and really tinier fraction, a fraction that is ever approaching 0.

6 0

4 years ago