Liquid leaking from a landfill is a big problem because it can contaminate ___

oksian1 [2.3K]

Answer:

Nations generally trade only one type of good or service

Explanation:

Specialization in business involves focusing on one product or a limited scope of products so as to become more efficient.

4 0

3 years ago

How can scientists use rock layers to determine when environmental changes occurred throughout Earth's history?

slega [8]

Scientists devised the geologic time scale after noticing differences in fossils as they progressed from oldest to youngest sedimentary strata. They divided Earth's past into many pieces of time when similar creatures were on the planet using relative dating.

Geological time units are based on visible, sequential changes in Earth's rock layers. In geology, the Law of Superposition asserts that sediment and rock strata are deposited in chronological order, with the oldest layers on the bottom and the youngest ones on top.

6 0

2 years ago

Como dice hola en ingles

Stella [2.4K]

Answer:

Hola: Hi

Adios: Bye

＞﹏＜

3 0

3 years ago

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How did Japan's geography help to control its territory and keep European traders out before the mid 1800s?

Marat540 [252]

Japan's geography help to control its territory and keep European traders out before the mid 1800s by: inland geography with mountains. Japan's geography help to control its territory and keep European traders out before the mid 1800s by: inland geography with mountains.

5 0

3 years ago

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Please answer this fast and here only

Vaselesa [24]

Answer:

1) a) $r_{R,I} = 1150\,m$ , b) $r_{R,II} = 3400\,m$ , c) $r_{R,III} = 2750\,m$ .

2) a) $r_{R,I} = 45,2\,km$ , b) $r_{R, II} = 28,15\,km$ , c) $r_{R,III} = 51,8\,km$ .

Explanation:

The scale factor is defined by the following expression:

$n = \frac{r_{S}}{r_{R}}$ (1)

Where:

$n$ - Scale factor.

$r_{S}$ - Scale distance, in centimetres.

$r_{R}$ - Real distance, in centimetres.

1) If we know that $n = \frac{1}{50000}$ , $r_{S,I} = 2,3\,cm$ , $r_{S,II} = 6,8\,cm$ and $r_{S,III} = 5,5\,cm$ , then the actual distances in metres are:

$r_{R,I} = \frac{r_{S,I}}{n}$

$r_{R,I} = \frac{2,3\,cm}{\frac{1}{50000} }$

$r_{R,I} = 115000\,cm$

$r_{R,I} = 1150\,m$

$r_{R,II} = \frac{r_{S,II}}{n}$

$r_{R,II} = \frac{6,8\,cm}{\frac{1}{50000} }$

$r_{R,II} = 340000\,cm$

$r_{R,II} = 3400\,m$

$r_{R, III} = \frac{r_{S, III}}{n}$

$r_{R,III} = \frac{5,5\,cm}{\frac{1}{50000} }$

$r_{R,III} = 275000\,cm$

$r_{R,III} = 2750\,m$

2) If we know that $n = \frac{1}{50000}$ , $r_{S, I} = 90,4\,cm$ , $r_{S, II} = 56,3\,cm$ and $r_{S,III} = 103,6\,cm$ , then the actual distance in kilometres is: