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photoshop1234 [79]

1 year ago

5

Help -x/3 > 5 A. X<15 B. X > -15 C. X < -15 D. X > 15

1 answer:

Genrish500 [490]1 year ago

8 0

Answer:

Steps

-x/3 >5

Multiply both sides by 3

3(-x/3)>5.3

Simplify

-X> 15

Multiply both sides by - 1 (reverse the inequality)

(-x)(-1)<15(-1)

Simplify

X< -15

so C is the answer

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a cone has a volume of 6 cubic inches. what is the volume of a cylinder that the cone fits exactly inside of

ella [17]

Answer:

= 18 cubic inches

Step-by-step explanation:

The volume of a cone is given by the formula;

V = 1/3 × base area × height

While that of cylinder is given by the formula;

Volume = Base area × height

Since we need the cylinder to fit exactly inside the cone, then it means that their bases are the same and heights are the same.

Therefore;

The cone has three times less volume compared to the cylinder.

Thus;

Volume of the cylinder = Volume of cone × 3

= 6 In³ × 3

<u>= 18 cubic inches</u>

5 0

3 years ago

A movie is 2 hours and 28 minutes long it starts at 7:20pm at what time will the movie end

umka2103 [35]

Movie starts 7:20 PM
2 hours = 02:00
28 minutes = 00:28

1.) 2 hours and 28 minutes = 02:28
2.) Movie starts 7:20 PM

You want to find out what time the movie will end

07:20 PM (start time)
+ 02:28 (movie time)
-------------------------------------
09:48 PM (movie end)

The movie will end at 9:48 PM

6 0

3 years ago

Read 2 more answers

Hey Bestie! 50 pts Pls help! Real answers only pls <3

frosja888 [35]

Answer:

$1. \: 3i$

2. option D

3. option C

4. option D

5. option C

6. option B

7. option C

8. option D

9. option C

10. option C

Step-by-step explanation:

<h2> $1. \: \sqrt{ - 9}$ </h2>

$\sqrt{ - 1(9)}$

$\sqrt{ - 1} \times \sqrt{ 9}$

$i \times \sqrt{9}$

$i \times \sqrt{ {3}^{2} }$

$i \times 3$

$3i$

<h2> $2. \: \sqrt{ - 8}$ </h2>

$\sqrt{ - 1(8)}$

$\sqrt{ - 1} \times \sqrt{8}$

$i \times \sqrt{8}$

$i \times \sqrt{ {2}^{2} \times 2 }$

$2i \sqrt{2}$

<h2> $3. \: \sqrt{ - 80}$ </h2>

$\sqrt{ - 1} \times \sqrt{80}$

$i \times \sqrt{80}$

$4i \: \sqrt{5}$

<h2> $4. \: \sqrt{ - 75}$ </h2>

$\sqrt{ - 1} \times \sqrt{75}$

$i \times \sqrt{75}$

$i \times \sqrt{ {5}^{2} \times 3 }$

$5i \sqrt{3}$

<h2> $5. \: \sqrt{ - 72}$ </h2>

$\sqrt{ - 1} \times \sqrt{72}$

$i \times \sqrt{72}$

$i \times ( {6}^{2} \times 2)$

$6i \sqrt{2}$

<h2> $6. \sqrt{ - 20}$ </h2>

$\sqrt{ - 1} \times \sqrt{20}$

$i \times \sqrt{20}$

$i \times \sqrt{ {2}^{2} \times 5}$

$2i \sqrt{5}$

<h2> $7. \: \sqrt{ - 27}$ </h2>

$\sqrt{ - 1} \times \sqrt{27}$

$i \times \sqrt{27}$

$i \times \sqrt{ {3}^{2} \times 3}$

$3i \sqrt{3}$

<h2> $8. \: \sqrt{ - 12}$ </h2>

$\sqrt{ - 1 \times 12}$

$i \times \sqrt{12}$

$i \times \sqrt{4(3)}$

$2i \sqrt{3}$

<h2> $9. \: \sqrt{ - 125}$ </h2>

$\sqrt{ - 1} \times \sqrt{125}$

$i \times \sqrt{ {5}^{2} \times 5 }$

$5i \sqrt{5}$

<h2> $10. \: \sqrt{ - 180}$ </h2>

$\sqrt{ - 1} \times \sqrt{180}$

$i \times \sqrt{ {6}^{2} \times 5 }$

$6i \sqrt{5}$

<h3>Hope it is helpful...</h3>

5 0

2 years ago

Solve each system by elimination.<br> 10x-6y=-8<br> -10x+6y=8

Step2247 [10]

Answer:

Infinitely Many Solutions

Step-by-step explanation:

$10x-6y=-8\\-10x+6y=8\\\0 = 0\\$

4 0

2 years ago

The equation tan(x- pi/3) is equal to _____.

kherson [118]

Answer:

B

Step-by-step explanation:

Using the expansion

tan(x - y) = $\frac{tanx-tany}{1+tanxtany}$ , then

tan(x - $\frac{\pi }{3}$ )

= $\frac{tanx-tan(-\frac{\pi }{3}) }{1+tanxtan(-\frac{\pi }{3}) }$

note that tan( - $\frac{\pi }{3}$ ) = - tan( $\frac{\pi }{3}$ ) = - $\sqrt{3}$

= $\frac{tanx-(-\sqrt{3}) }{1+tanx(-\sqrt{3}) }$

= $\frac{tanx+\sqrt{3} }{1-\sqrt{3}tanx }$ → B

6 0

3 years ago

Read 2 more answers