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2 years ago

4n^2-15n-25 factor trinomials pls help me on this i would love if you would put the steps too thank you

Mathematics

1 answer:

velikii [3]2 years ago

3 0

---Multiply a x c

Quadratic Form: ax^2 + bx + c

4 x -25 = -100

---Find a factor pair of -100 that adds up to -15

-20 x 5 = - 100

-20 + 5 = -15

---Separate the b term into your two factors

4n^2 + 5n - 20n - 25

This can take some trial and error (though there are only two options) because when you factor, you want the inside of the parentheses to be the same. If you look at the next step, (4n + 5) appears twice.

---Factor each binomial

n(4n + 5) - 5 (4n + 5)

---Rewrite

(n - 5)(4n + 5)

What you're really doing here is factoring out the (4n + 5), which leaves you with the terms that you factored out in the previous step. You then combine these terms into one set of parenthesis.

Answer: (n - 5)(4n + 5)

Hope this helps!

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Shkiper50 [21]

Answer:

Step-by-step explanation:

H(3,2) & J(4, 1)

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Line HJ and KM have same slopes. So, they are parallel

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3 years ago

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3 years ago

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4 years ago

Last June only 0.17 inches of rain fell all month. What is the difference between the average rainfall and the actual rainfall f

spin [16.1K]

Answer:

Part 1) 0.50 inches

Part 2) 1.14 inches

Part 3)

a) 1.25 inches

b) -0.32 inches

Step-by-step explanation:

The complete question in the attached figure

Part 1) Last June only 0.17 inches of rain fell all month. What is the difference between the average rainfall and the actual rainfall for the last June

Let

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

The difference between the average rainfall and the actual rainfall for the last June is given by the expression

$(x-y)$

we have

$x=0.67\ in\\y=0.17\ in$

substitute

$0.67-0.17=0.50\ in$

Part 2) The departure from the average rainfall last July was -0.36 inches. How much rain fell last July?

we know that

The departure from the average is the difference between the actual amount of rain and the average amount of rain for a given month

Let

D -----> the departure from the average

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

$D=y-x$

we have

$D=-0.36\ in\\x=1.5\ in$

substitute the given values

$-0.36=y-1.5$

solve for y

$y=1.5-0.36\\y=1.14\ in$

Part 3)

<u>Part a)</u> How much rain would have to fall in August so that the total amount of rain equals the average rainfall for these three months?

<u>Part b</u>) What would the departure from the average be in August in that

situation?

Part a) How much rain would have to fall in August so that the total amount of rain equals the average rainfall for these three months?

Find the average rainfall for these three months

Adds the average rainfall and divide by 3

$(0.67+1.5+1.57)/3=1.25\ in$

Part b) What would the departure from the average be in August in that

situation?

we know that

The departure from the average is the difference between the actual amount of rain and the average amount of rain for a given month

Let

D -----> the departure from the average

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

$D=y-x$

we have

$x=1.57\ in\\y=1.25\ in$

substitute the given values

$D=1.25-1.57=-0.32\ in$

7 0

4 years ago

A triangle with exterior angles is shown. A triangle sits on a line and forms 2 exterior angles on the left and right of the tri

NARA [144]

Answer:

Option 3.

Step-by-step explanation:

It is given that a triangle sits on a line and forms 2 exterior angles on the left and right of the triangle of (2h) degrees.

The top interior angle of the triangle is 40 degrees.

$\angle BAC=40$

From the given figure it is clear that

$\angle ABC+2h=180$ (Supplementary angle)

$\angle ABC=180-2h$

$\angle ACB+2h=180$ (Supplementary angle)

$\angle ACB=180-2h$

According to the angle sum property of triangle, the sum of all interior angles of a triangle is 180 degree.

$\angle ABC+\angle ACB+\angle BAC=180$

$(180-2h)+(180-2h)+40=180$

Combine like terms.

$(180+180+40)+(-2h-2h)=180$

$400-4h=180$

$-4h=180-400$

$-4h=-220$

Divide both sides by -4.

$h=\frac{-220}{-4}$

$h=55$

The value of h is 55.

Therefore, the correct option is 3.

8 0

4 years ago

Read 2 more answers