There are 12 dimes and 19 nickels
<h3>The required simultaneous equations</h3>
Since Jace has $2.15 in nickels and dimes.
We know that 1 nickel = $ 0.05 and 1 dime = $0.10
Let
- n = number of nickels and
- n' = number of dimes
We have that
0.05n + 0.10n' = 2.15 (1)
Since he has 7 more nickels than dimes, we have that
n = n' + 7 (2)
<h3>The number of dimes</h3>
Substituting equation (2) into (1), we have
0.05n + 0.10n' = 2.15 (1)
0.05(n' + 7) + 0.10n' = 2.15
0.05n' + 0.35 + 0.10n' = 2.15
0.15n' + 0.35 = 2.15
0.15n' = 2.15 - 0.35
0.15n' = 1.8
n' = 1.8/0.15
n' = 12
<h3>The number of nickels, </h3>
Since the number of nickels, n = n' + 7
Substituting n = 12 into the equation, we have
n = n' + 7
n = 12 + 7
n = 19
So, there are 12 dimes and 19 nickels
Learn more about simultaneous equations here:
brainly.com/question/21654746
