All categories

2 years ago

PLEASE HELP ASAP

Mathematics

2 answers:

Lelu [443]2 years ago

7 0

Answer:

$y= -\dfrac{5}{3} x+7$

In order to find equation:

Find slope:

$\sf slope: \dfrac{y_2- y_1}{x_2 -x_1} = \dfrac{rise}{run}$ where (x1, y1), (x2, y2)

$\hookrightarrow \sf slope: \dfrac{-3-2}{6-3}$

$\hookrightarrow \sf slope:- \dfrac{5}{3}$

Find Equation:

$\boxed{\sf y - y_1 = m(x_1 -x)}$ "m" is slope

$\sf \rightarrow y-2 = -\dfrac{5}{3} (x-3)$

$\sf \rightarrow y-2 = -\dfrac{5}{3} x+5$

$\sf \rightarrow y= -\dfrac{5}{3} x+5+2$

$\sf \rightarrow y= -\dfrac{5}{3} x+7$

Svetradugi [14.3K]2 years ago

4 0

Answer:

(y+2)=2(x−3)

(y−4)=2(x-6)

y=2x−8

Step-by-step explanation:

You might be interested in

25% discount off of $350 Original: Discount: New price: Plz help

devlian [24]

Original:350 discount:87.50 off new price: 262.5

4 0

3 years ago

Read 2 more answers

the weight of a bucket is 33/2 kg. if 1/4 of the bucket contains water weighing 21/4 kg , determine the weight of empty bucket

Sauron [17]

Answer:

15.733kg

Step-by-step explanation:

33.2 - 21.4 = 11.8

3/4 of the bucket empty is 11.8kg.

11.8 divided by 3 is 3.933. 3.933 x 4 is 15.733

7 0

3 years ago

URGENT DUE IN 20 MINUTES FOR GRADE PLEASE HELP 2/3 (x-7)= -2

ASHA 777 [7]

2/3 (x-7)= -2
x - 7 = -2 * 3/2
x - 7 = -3
x = -3 + 7
x = 4

7 0

3 years ago

A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot

ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = $(x\times x)$

$=x^2$

The volume of the box is = area of the base × height

$=x^2h$

Therefore,

$x^2h=272$

$\Rightarrow h=\frac{272}{x^2}$

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

$=20x^2$ cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

$=10x^2$ cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

$=4xh\times 1.5$ cents

$=6xh$ cents

Total cost = $(20x^2+10x^2+6xh)$

$=30x^2+6xh$

Let

C $=30x^2+6xh$

Putting the value of h

$C=30x^2+6x\times \frac{272}{x^2}$

$\Rightarrow C=30x^2+\frac{1632}{x}$

Differentiating with respect to x

$C'=60x-\frac{1632}{x^2}$

Again differentiating with respect to x

$C''=60+\frac{3264}{x^3}$

Now set C'=0

$60x-\frac{1632}{x^2}=0$

$\Rightarrow 60x=\frac{1632}{x^2}$

$\Rightarrow x^3=\frac{1632}{60}$

$\Rightarrow x\approx 3$

Now $C''|_{x=3}=60+\frac{3264}{3^3}>0$

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is $=\frac{272}{3^2}$

=30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0

3 years ago

What are formed by perpendicular lines

Karolina [17]

Answer:

Right angles

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers