Answer: Area of ΔAPC = 70 square meter and Area of △PMC= 35 square meter
Step-by-step explanation:
Here, AM is a median in △ABC (M∈ BC ). A line drawn through point M intersects AB at its midpoint P.
Since, we know that median divides a triangle into equal areas.
Therefore, By the diagram we can say that If Area of ΔAPM=35 .
Therefore Area of ΔBPM = 35 ( Because MP is the median of triangle MAB.)
⇒ Area of ΔPMC = 35 ( Because MP is the median of triangle PBC.)
Now, Area of ΔAPC= Area of ΔPBC ( CP is the median of ΔABC)
But area of ΔPBC= Area of ΔBPM+ area of ΔPMC= 35+35=70 square unit.
⇒ Area of Δ APC= 70 square unit.
