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Anni [7]
2 years ago
5

Transform each polar equation to an equation in rectangular form.

Mathematics
1 answer:
pickupchik [31]2 years ago
4 0

The equation of the line in slope-intercept form is equal to y = √3x + b.

<h3>How to transform polar coordinates to rectangular coordinates?</h3>

In geometry, the relationship between a rectangular coordinate (x, y) and a polar coordinate (r, θ) based on the conversion rules is given by these polar functions:

x = rcosθ    ....equation 1.

y = rsinθ     ....equation 2.

<u>Where:</u>

  • θ is the angle.
  • r is the radius of a circle.

Also, the slope from this angle is given by:

θ = tan⁻¹(y/x)

tan⁻¹ (π/3) = (y/x)

√3 = (y/x)

y = √3x

Mathematically, the equation of the line in slope-intercept form is given by this formula;

y = √3x + b.

Read more on polar coordinates here: brainly.com/question/2193539

#SPJ1

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If the value of y varies directly with x when y=50, x=4. What is the value of y when x=2
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Answer:

Step-by-step explanation:

The general equation for a direct variation is y = k*x

So your first step (usually) is to find k

y = k x

when x = 4

then y = 50

  • y = k*x
  • 50 = k * 4              Divide by 4
  • 50 / 4 = k*4/4
  • 12.5 = k

Now you can find the value of y when x = 2

  • y = k*x
  • k = 12.5
  • x = 2
  • y = ?

y = 12.5 * 2

y = 25

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A rectangle prism has three dimension
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Step-by-step explanation:

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Which problems can be solved by performing this multiplication?
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The coordinates of the midpoint of GH are M(-2, 0), and the coordinates of one endpoint are H(4,-4).
Svetlanka [38]

The coordinate of point S from the giving coordinate point is (-8,4)

<h3>Midpoint of coordinates</h3>

The formula for calculating the midpoint of coordinate point is expressed as:

M(x,y) = {(x₁+x₂)/2, (y₁+y₂)/2}

Determine the measure of the coordinate S
-2 = 4+x₂/2

2(-2) = 4+x₂

x₂ = -4-4

x₂ = -8

Similarly

0 = -4+y₂/2

0(2) = -4+y₂

y₂ = 4

Hence the coordinate of point S from the giving coordinate point is (-8,4)

Learn more on midpoint here: brainly.com/question/5566419

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